Answer:
The fourth pair of statement is true.
9∈A, and 9∈B.
Step-by-step explanation:
Given that,
U={x| x is real number}
A={x| x∈ U and x+2>10}
B={x| x∈ U and 2x>10}
If 5∈ A, Then it will be satisfies x+2>10 , but 5+2<10.
Similarly, If 5∈ B, Then it will be satisfies 2x>10 , but 2.5=10.
So, 5∉A, and 5∉B.
If 6∈ A, Then it will be satisfies x+2>10 , but 6+2<10.
Similarly, If 6∈ B, Then it will be satisfies 2x>10 , and 2.6=12>10.
So, 6∉A, and 6∈B.
If 8∈ A, Then it will be satisfies x+2>10 , but 8+2=10.
Similarly, If 8∈ B, Then it will be satisfies 2x>10. 2.8=16>10.
So, 8∉A, and 8∈B.
If 9∈ A, Then it will be satisfies x+2>10 , but 9+2=11>10.
Similarly, If 9∈ B, Then it will be satisfies 2x>10. 2.9=18>10.
So, 9∈A, and 9∈B.
Answer:
hope it helps you thank you
Step-by-step explanation:
mark me as brilliant
Answer:
First you have to multiply negative four in parentheses, then add minus two
-4×(-8+3x)=32-12x
2+32-12x=34-12x
34-12x=82
-12x=48
x=-4
Answer:
x=3
Step-by-step explanation:
f(x) = 2^x
Let f(x) =8
8 = 2^x
Rewriting 8 as 2^3
2^3 = 2^x
The bases are the same so the exponents are the same
3=x
No one can help you if you dont show us the work my dude. But the was to convert them is say you have 1/4 that is 25% of a whole. Sorry i couldnt help more repost the question with a link and people can help then.
