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tigry1 [53]
3 years ago
11

6j-k=233k+6j=11Solve j and k ​using the elimination method on the simultaneous equations

Mathematics
1 answer:
frez [133]3 years ago
5 0

Answer:

Step-by-step explanation:

6j - k = 23

6j + 3k = 11.....multiply by -1

---------------

6j - k = 23

-6j - 3k = -11 (result of multiplying by -1)

---------------

-4k = 12

k = -12/4

k = - 3 <=====

6j - k = 23

6j - (-3) = 23

6j + 3 = 23

6j = 23 - 3

6j = 20

j = 20/6

j = 10/3 <===

solution is : j = 10/3 and k = -3

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A teacher writes a simple computer program where she can type students name and computer tells her the students birthday.
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<h3>When does a relation represent a function?</h3>

A relation represents a function when each value of the input is mapped to only one value of the output.

For this problem, we have that:

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5 0
1 year ago
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trasher [3.6K]

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Given that,
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<h3>What is simplification?</h3>

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Question asked to simplify the term 9(m-9)-4(10m+2).

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2 years ago
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