Answer is C. y=1/3x+3
the slope is going to be 1/3 (opposite of -3/1) and if go to the point 3,4 and go down one and left 3, you will get a y intercept as 3
It would be 1/3rd because your last number would be 4 in the equation of 12 sandwiches.
Answer:
u=54
Step-by-step explanation:
VX is middle line of triangle, so
VX=ZY/2.....(1)
We know that
Zy=u
Vx=u-27
Put that in (1) we have:
u-27=u/2
2u-54=u
2u-u=54
u=54
Answer:
Step-by-step explanation:
x^-y=1/(x^y) so 3t^-4=3/(t^4)
If <em>x</em>² + <em>y</em>² = 1, then <em>y</em> = ±√(1 - <em>x</em>²).
Let <em>f(x)</em> = |<em>x</em>| + |±√(1 - <em>x</em>²)| = |<em>x</em>| + √(1 - <em>x</em>²).
If <em>x</em> < 0, we have |<em>x</em>| = -<em>x</em> ; otherwise, if <em>x</em> ≥ 0, then |<em>x</em>| = <em>x</em>.
• Case 1: suppose <em>x</em> < 0. Then
<em>f(x)</em> = -<em>x</em> + √(1 - <em>x</em>²)
<em>f'(x)</em> = -1 - <em>x</em>/√(1 - <em>x</em>²) = 0 → <em>x</em> = -1/√2 → <em>y</em> = ±1/√2
• Case 2: suppose <em>x</em> ≥ 0. Then
<em>f(x)</em> = <em>x</em> + √(1 - <em>x</em>²)
<em>f'(x)</em> = 1 - <em>x</em>/√(1 - <em>x</em>²) = 0 → <em>x</em> = 1/√2 → <em>y</em> = ±1/√2
In either case, |<em>x</em>| = |<em>y</em>| = 1/√2, so the maximum value of their sum is 2/√2 = √2.
