The perimeter of a rectangle is 108cm. The ration of its length to its width is 7:2 what is the area of the rectangle in cm2?
1 answer:
Answer:
504 cm²
Step-by-step explanation:
Let the length and the width of the rectangle be L cm and W cm respectively.
Perimeter= 2(L +W)
2(L +W)= 108
L +W= 108 ÷2
L +W= 54
L= 54 -W -----(1)
<em>Cross multiply:</em>
2L= 7W -----(2)
Substitute (1) into (2):
2(54 -W)= 7W
<em>Expand:</em>
108 -2W= 7W
<em>+2W on both sides:</em>
9W= 108
<em>Divide both sides by 9:</em>
W= 108 ÷9
W= 12
<em>Substitute W= 12 into (1):</em>
L= 54 -12
L= 42
Area of rectangle
= length ×width
= LW
= 42(12)
= 504 cm²
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Answer:
Option D
Step-by-step explanation:
By the property of intersecting chords,
If two chords are intersecting at a point inside a circle, product of lengths of the line segments on each chord is equal.
DI × EI = HI × GI
12 × EI = 8 × 6
EI =
EI = 4
Therefore, Option D is the correct option.