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3 years ago

Which sentence explains the correct first step in the solution of this equation? 4(−3)=9

Mathematics

1 answer:

stellarik [79]3 years ago

7 0

The answer to the following equation is x = 5.25

Step-by-step explanation:

4(X-3)=9

Multiplying 4 with x and 3 in the bracket

4x-12=9

shifting 12 on the left hand side,therefore

4x=9+12;

4x = 21

x= 21/4

therefore,

x= 5.25

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nexus9112 [7]

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3 years ago

Brainliest question please help please help me now plz

Kruka [31]

Answer:

Option A) Inside the circle

Step-by-step explanation:

step 1

Find the radius of the circle

we know that

The radius is equal to the distance from the center to any point on the circle

the formula to calculate the distance between two points is equal to

$d\sqrt{(y2-y1)^2+(x2-x1)^2 }$

we have

A(-5,-8),M(-1,-3)

substitute the values

$r=\sqrt{(-3+8)^{2}+(-1+5)^{2}}$

$r=\sqrt{(5)^{2}+(4)^{2}}$

$r=\sqrt{41}\ units$

step 2

Find the distance from the center to point V

we know that

If the distance from the center to point V is equal to the radius, then the point V lie on the circle

If the distance from the center to point V is less than the radius, then the point V lie inside the circle

If the distance from the center to point V is greater than the radius, then the point V lie outside the circle

we have

A(-5,-8),V(-11,-6)

substitute in the formula

$d=\sqrt{(-6+8)^{2}+(-11+5)^{2}}$

$d=\sqrt{(2)^{2}+(-6)^{2}}$

$d=\sqrt{40}\ units$

$\sqrt{40}\ units< \sqrt{41}\ units$

The distance from the center to point V is less than the radius

therefore

The point V lie inside the circle

Hope that helped :)

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3 years ago

The answer to the question

Andru [333]

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Read 2 more answers

If (w+13)^2=(3w+7)(2w+4), find w^2. Express your answer as a decimal.

faltersainse [42]

Answer: w² equals to 28.2

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4 years ago

How solve this <br> x+y=5<br> X-y=7

Misha Larkins [42]

$elimination\ methode\\\\\underline{+\left\{\begin{array}{ccc}x+y=5\\x-y=7\end{array}\right}\ \ \ \ |add\ both\ sides\ of\ the\ equations\\.\ \ \ \ \ \ 2x=12\ \ \ \ \ |divide\ both\ sides\ by\ 2\\.\ \ \ \ \ \ \ \boxed{x=6}\\\\subtitute\ the\ value\ of\ x\ to\ the\ first\ equation:\\\\6+y=5\ \ \ \ |subtract\ 6\ from\ both\ sides\\\boxed{y=-1}\\\\Answer:\boxed{\left\{\begin{array}{ccc}x=6\\y=-1\end{array}\right}$

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4 years ago