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Dvinal [7]
3 years ago
7

In ΔEFG, the measure of ∠G=90°, the measure of ∠E=40°, and EF = 75 feet. Find the length of GE to the nearest tenth of a foot

Mathematics
2 answers:
juin [17]3 years ago
5 0

Answer:

19.4 feet

Step-by-step explanation:

Since the triangle has a right angle( as one of the angles in it is equal to 90°), we may find the length of the unknown side using the trigonometric notations SOH CAH TOA where

SOA stands for

Sin Ф = opposite side/hypotenuses side

Cosine Ф = adjacent side/hypotenuses side

Tangent Ф = opposite side/adjacent side

Given that the measure of ∠G=90° and  ∠E=40°

EF is the hypotenuse side

FG is the opposite side and

GE is the adjacent side. As such if EF = 75 feet

Cos 75 = GE/75

GE = 75 Cos 75°

= 19.41 feet

≈ 19.4 feet in the nearest tenth of a foot

luda_lava [24]3 years ago
4 0

Answer:

57.5

Step-by-step explanation:

i got it wrong becz of the person above me and ended up finding out the answer lol (this is probably too late anyway)

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Write the expression in its written form. 3/8×(1−13)
kaheart [24]

Answer:

7 /8

0.875

Step-by-step explanation:

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3 years ago
A clerk has 1/2 book of stamps on Monday. On Tuesday, he used 1/10 of the book of stamps. How much of the book of stamps is left
Lapatulllka [165]

Answer: B. 2/5 of the book.


6 0
3 years ago
Read 2 more answers
Your Assignment: Furry Friends
Levart [38]

2. Create frequency tables to represent the morning and afternoon dogs as two sets of data. Group the weights into classes that range 10 pounds. (4 points: 2 points for appropriate intervals, 2 points for correctly portraying data)

Morning

Range

Dogs

10 to 19

3

20 to 29

4

30 to 39

3

Afternoon

Range

Dogs

0 to 9

2

10 to 19

3

20 to 29

1

30 to 39

2

40 to 49

1

50 to 59

1

3. What is the median of the morning (AM) group? What is the median of the afternoon (PM) group? (2 points: 1 point for each answer)

Morning (AM): 25.5

Afternoon (PM): 19

4. What is the first quartile (Q1) of the morning (AM) group? What is the first quartile (Q1) of the afternoon (PM) group? (2 points: 1 point for each answer)

Morning (AM): 10

Afternoon (PM): 0

5. What is the third quartile (Q3) of the morning (AM) group? What is the third quartile (Q3) of the afternoon (PM) group? (2 points: 1 point for each answer)

Morning (AM): 20

Afternoon (PM): 10

6. What is the interquartile range (IQR) of the morning (AM) group? What is the interquartile range (IQR) of the afternoon (PM) group? (2 points: 1 point for each answer)

Morning (AM): 39

Afternoon (PM): 29

7. The average weights of the dogs are the same for the morning and afternoon groups. But based on your comparative box plot and the IQRs of the two groups, which group of dogs does you think would be easier to walk as one group? Why? (2 points: 1 point for the answer, 1 point for justification)

The morning dogs, there are fewer dogs and they seem to weigh less.

All of the answers I have here!

5 0
3 years ago
Can yall please help me
Murrr4er [49]

Answer:

8.)12

Step-by-step explanation:

The answer to number 8 would be twelve because.....

if he read 4 pages in 8 minutes he is reading a page in 2 minutes so basically you could multiplt the number of pages he read by 2 and that would give you the answer.

4 0
4 years ago
Please answer this in two minutes
inysia [295]

Answer:

x = 5.7 units

Step-by-step explanation:

By applying Sine rule is the triangle XYZ,

\frac{\text{SinX}}{\text{WY}}=\frac{\text{SinY}}{\text{WX}}=\frac{\text{SinW}}{\text{XY}}

\frac{\text{SinX}}{\text{x}}=\frac{\text{SinY}}{\text{y}}=\frac{\text{SinW}}{\text{10}}

\frac{\text{Sin33}}{\text{x}}=\frac{\text{SinY}}{\text{y}}=\frac{\text{Sin107}}{\text{10}}

\frac{\text{Sin33}}{\text{x}}=\frac{\text{Sin107}}{\text{10}}

x=\frac{10\times(\text{Sin33})}{\text{(Sin107)}}

x = 5.69

x ≈ 5.7 units

7 0
4 years ago
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