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Darya [45]
3 years ago
15

From 5 employees at a company, a group of 3 employees will be chosen to work on a project. How many different groups of 3 employ

ees can be chosen?
Mathematics
2 answers:
Andrei [34K]3 years ago
8 0
Hello,

aPb=b*(b-1)*(b-2)*....*(b-a+1) / a!

3P5=5*4*3/(3*2*1)=10

If we name the number of the employers 1,2,3,4,5

Here are the choices:

123,124,125,134,135,145,234,235,245,345 (total 10 choices)

adoni [48]3 years ago
8 0
Based on the problem above the answer is 10. Below is the solution: 

<span>formula is 5! / 3! * (5-3)! = 5*4*3*2*1 / 3*2*2 = 10 combinations

There are 10 combination that are from 5 employees taken 3 at a time.</span>
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Answer:

Therefore there are 35 number of 2-point questions and 15 number of 5-point questions.

Step-by-step explanation:

i) let the number of 2 point question is x.

ii) let the number of 5 point questions be y

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iv) therefore x + y = 50

v) it is also given that 2x + 5y = 145

vi) solving for the two equations found in iv) and v). Multiplying iv) by 2 we get

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vii) subtracting equation vi) from equation v) we get 3y = 45.

viii) Therefore y = 15.

ix) using the value in viii) and substituting in iv) we get x + 15 = 50.

    Therefore x = 50 - 15  = 35

x) Therefore there are 35 number of 2-point questions and 15 number of 5-point questions.

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Answer:

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