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enyata [817]
3 years ago
6

Help me!!!!!!!!!!!!!!

Mathematics
2 answers:
kogti [31]3 years ago
6 0
the cost per pound of apples in 2.50$. You can buy 4 pounds with 30$. 3 apples I'm each pound 50 apples
HACTEHA [7]3 years ago
4 0
Cost per pound 5.00/2 = $2.50 per pound
$30.00/$2.50 = 12 You can buy 12 pounds of apples for $30
16/5 = 3.2   There are about 3 apples per pound
12*3 = 36  You can buy approx 36 apples for $30
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What is the measure of angle OAC if major arc AB
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Answer: A. 55°

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What is the perimeter of the triangle in the diagram?<br><br><br> a + b + <br> a2 + b2<br> 2(a + b)
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Find the volume of a pyramid with a square base, where the perimeter of the base is
Kobotan [32]

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6.8 cubic feet

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4 0
3 years ago
Suppose that a large mixing tank initially holds 500 gallons of water in which 50 pounds of salt have been dissolved. Another br
Lina20 [59]

Answer:

The differential equation for the amount of salt A(t) in the tank at a time  t > 0 is \frac{dA}{dt}=12 - \frac{2A(t)}{500+t}.

Step-by-step explanation:

We are given that a large mixing tank initially holds 500 gallons of water in which 50 pounds of salt have been dissolved. Another brine solution is pumped into the tank at a rate of 3 gal/min, and when the solution is well stirred, it is then pumped out at a slower rate of 2 gal/min.

The concentration of the solution entering is 4 lb/gal.

Firstly, as we know that the rate of change in the amount of salt with respect to time is given by;

\frac{dA}{dt}= \text{R}_i_n - \text{R}_o_u_t

where, \text{R}_i_n = concentration of salt in the inflow \times input rate of brine solution

and \text{R}_o_u_t = concentration of salt in the outflow \times outflow rate of brine solution

So, \text{R}_i_n = 4 lb/gal \times 3 gal/min = 12 lb/gal

Now, the rate of accumulation = Rate of input of solution - Rate of output of solution

                                                = 3 gal/min - 2 gal/min

                                                = 1 gal/min.

It is stated that a large mixing tank initially holds 500 gallons of water, so after t minutes it will hold (500 + t) gallons in the tank.

So, \text{R}_o_u_t = concentration of salt in the outflow \times outflow rate of brine solution

             = \frac{A(t)}{500+t} \text{ lb/gal } \times 2 \text{ gal/min} = \frac{2A(t)}{500+t} \text{ lb/min }

Now, the differential equation for the amount of salt A(t) in the tank at a time  t > 0 is given by;

= \frac{dA}{dt}=12\text{ lb/min } - \frac{2A(t)}{500+t} \text{ lb/min }

or \frac{dA}{dt}=12 - \frac{2A(t)}{500+t}.

4 0
3 years ago
In the equation Y = 8x+ 5 the name for y are​
VLD [36.1K]

Answer:

The equation of any straight line, called a linear equation, can be written as: y = mx + b, where m is the slope of the line and b is the y-intercept. The y-intercept of this line is the value of y at the point where the line crosses the y axis.

Step-by-step explanation:

4 0
3 years ago
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