The third graph represents a function.
In a function, every input (x value) has <em>exactly</em> one output (y value). If even a single input has zero or two outputs, the graph does not represent a function.
A good way of testing this is using a vertical line. As you move a vertical line from left to right across a graph, it should always be touching exactly one point on the graphed line.
In this case, every graph fails this vertical line test except for the third graph, so the third graph represents a function.
Answer:
3
______
4 | 12
-12
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Step-by-step explanation:
12/4
The top number always goes inside (larger or not), and the bottom number always goes on the outside (larger or not).
______
4 | 12
Ask yourself how many 4's are in 12.
Let's see one 4 is just 4.
We can probably do more 4's than that.
Two 4's gives us 4+4=8.
Let's see if we can put one 4 in there.
Three 4's gives us 4+4+4=12.
So we can fit three 4's into 12 and there is nothing left over.
3
______
4 | 12
-12 (since 4 times 3 or 4+4+4 is 12)
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Answer:
The answer is B)
Step-by-step explanation:
Use the Distance Formula
d = sqr(1 + 3)^2 + (0 - 4)^2
d = sqrt(32)
d = 4*sqrt(2)
Answer: e. 
Step-by-step explanation:
1. You have the following expression given in the problem:

2. To solve the exercise and find an equal expression, you must simplify that expression. Apply the Distributive property. Multiply the terms inside the parentheses by
. Then, you obtain:

To solve this problem you must apply the proccedure shown below:
1. You have to find the radius <span>of convergence of the following Maclaurin series:
</span>

2. Let's take the denominator and find the roots:

3. The roots are

and the distance from the origin is

.
Therefore, the answer is: