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Marta_Voda [28]
3 years ago
11

Your mum has saved £12000 and agreed to give you share would your answer be in fraction

Mathematics
1 answer:
sattari [20]3 years ago
5 0
1/5 if you want the majority

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Express in simplest radical form.<br> \frac{\sqrt{96}}{2}
Gelneren [198K]

Answer:

\frac{ \sqrt{96} }{2}  =  \frac{ \sqrt{16 \times 6} }{2}  =  \frac{4\sqrt{6} }{2}  = \boxed{2 \sqrt{6}}\\

<h3><em><u>2√6</u></em> is the right answer.</h3>
8 0
3 years ago
PLEASE HELP!
fenix001 [56]

Answer:

No

Step-by-step explanation:

No because (1,2) falls on the line, and the line is a dotted line, which means that any point on the line is not a solution to the inequality.

5 0
3 years ago
Solve -7(3x-7)+21x_&gt;50
ohaa [14]

Answer:

There are no solutions.

Step-by-step explanation:

Let's solve your inequality step-by-step.

−7(3x−7)+21x≥50

6 0
3 years ago
I need to write the equation in slope intercept form that passes through the points
VMariaS [17]
(x1, y1) (x2, y2)
(-4, 5)    (-1, 1)
x2-x1 
-1 - -4
-1+4
   3
y2-y1
1- -4
1+4
  5
 
answer : (3,5)
I believe this is right, hope this helps!


4 0
3 years ago
The population of a particular type of bacteria is known to triple in 22 days. What is the daily growth rate
Paul [167]

Answer: ∛(3)

Step-by-step explanation:

Suppose that at day 0 the population was A.

at day 3, the population will be: 3*A

at day 6, the population will be 3*(3*A) = A*3^2

then, at day N = 3*n (where n = 0, 1, 2.....) the population will be:

P(N) = A*3^n

Particularly, if we take n = 1/3 we will have:

N = 3*1/3 = 1

This means that this is the first day after the day 0.

P(1) = A*3^(1/3)

(then in day one, the population grow by a factor of 3^(1/3))

N = 2 is when n = 2/3, then:

P(2) = A*3^(2/3)

The quotient between P(2) and P(1) is equal to the growth between day one and day two, this should be the same as the growth between day zero and day one.

A*3^(2/3)/(A*3^(1/3)) = 3^( 2/3 - 1/3) = 3^(1/3)

So we found that the daily growth rate is 3^(1/3) or ∛(3)

3 0
3 years ago
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