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Artist 52 [7]
3 years ago
12

Please Help.

Mathematics
2 answers:
Bond [772]3 years ago
6 0
5 x 6 + 7? Is that what the answer is, I didn't get the question towards the end. :)
grandymaker [24]3 years ago
3 0
37-7=30
30/6=5 
(37-7)/6=5
or.....
6*5+7=37
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What is 5 1/6 divided by (2 2/3 multiplied by 1 3/8)
Karo-lina-s [1.5K]
So first you need your denominators to be the same so you can multiply. They share a common denominator of 24. 2/3 equals 16/24 and 2/8 equals 9/24. So now you need to turn your fractions into mixed numbers and multiply. Which equals 2112/576. That # is way to big so then you simplify and get 11/3. so now you have 5 and 1/6 divided by 11/3. So now just flip the second fraction multiply it by its reciprocal. 31/6 X 3/11=___. So your final answer is 1 and 9/22

3 0
3 years ago
a school district collected 14,621 pounds of recyclables during last year. This year was 3,943 more pounds of recyclables than i
Zepler [3.9K]

Answer:

14,621 lbs.

Step-by-step explanation:

It says at the beginning of the question that the school district collected 14,621 lbs. of recycling. The part where it says that the school district collected 3,943 lbs. of recycling more than last year is un-needed information.

8 0
3 years ago
Megan has a large packing box shaped as a cube with a volume of 216 cubic feet.
Flura [38]

Answer:

s = 6 feet

Step-by-step explanation:

Given that,

The volume of the cube, V = 216 feet³

We need to find the side length for the cubical box. We know that the volume of the cube is given by :

V=s^3, s is the side length of the box.

So,

s={V}^{1/3}\\\\s={216}^{1/3}\\\\s=6\ feet

So, the side length for the cubical box is equal to 6 feet.

6 0
3 years ago
In the △ABC, the height AN = 24 in, BN = 18 in, AC = 40 in. Find AB and BC. Consider all possible cases. Case 1 : N∈BC, AB = __,
aivan3 [116]

Answer:

Case 1:

AB = 30

BC = 50

Case 2:

AB = 15.9

BC = 36.7

Case 3: Not possible

Step-by-step explanation:

Given

See attachment for illustration of each case

Required

Find AB and BC

Case 1:

Using Pythagoras theorem in ANB, we have:

AB^2 = AN^2 + BN^2

This gives:

AB^2 = 24^2 + 18^2

AB^2 = 576 + 324

AB^2 = 900

Take square roots of both sides

AB = \sqrt{900

AB = 30

To calculate BC, we consider ANC, where:

AC^2 = AN^2 + NC^2

40^2 = 24^2 + NC^2

1600 = 576 + NC^2

Collect like terms

NC^2 = 1600 - 576

NC^2 = 1024

Take square roots

NC = \sqrt{1024

NC = 32

So:

BC = NC + BN

BC = 32 + 18

BC = 50

Case 2:

Using Pythagoras theorem in ANB, we have:

AN^2 = AB^2 + BN^2

This gives:

24^2 = AB^2 + 18^2

576 = AB^2 + 324

Collect like terms

AB^2 = 576 - 324

AB^2 = 252

Take square roots of both sides

AB = \sqrt{252

AB = 15.9

To calculate BC, we consider ABC, where:

AC^2 = AB^2 + BC^2

40^2 = 252 + BC^2

1600 = 252 + BC^2

Collect like terms

BC^2 = 1600 - 252

BC^2 = 1348

Take square roots

BC = \sqrt{1348

BC = 36.7

Case 3:

This is not possible because in ANC

The hypotenuse AN (24) is less than AC (40)

3 0
2 years ago
Multiple choice for final pls help me
prohojiy [21]

Answer:

I hope this helps!

Step-by-step explanation:

ACB

5 0
3 years ago
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