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Artist 52 [7]
3 years ago
12

Please Help.

Mathematics
2 answers:
Bond [772]3 years ago
6 0
5 x 6 + 7? Is that what the answer is, I didn't get the question towards the end. :)
grandymaker [24]3 years ago
3 0
37-7=30
30/6=5 
(37-7)/6=5
or.....
6*5+7=37
You might be interested in
Which only lists multiples of 16? O1,2,4, 8, 16 O 16, 24, 32, 40 O16, 32, 48, 64 O 1,2, 4, 8, 12, 16​
schepotkina [342]

Answer:

48 & 68

Step-by-step explanation:

if you multiply the numbers you will see that you get 48 & 68 multiple times

5 0
3 years ago
Retro Rides is a club for owners of vintage cars and motorcycles. Every year the club gets together for a ride. This year, 53 ve
kari74 [83]
21 cars, 32 motorcycles.
create a system of equations using x for cars and y for motorcycles.
\left \{ {{x+y=53} \atop {4x+2y=148}} \right.
multiply the top equation by 2 to prepare for elimination method
\left \{ {{2x+2y=106} \atop {4x+2y=148}} \right.
subtract terms
\left \{ {{2x+2y=106} \atop {-4x-2y=-148}} \right.  = (-2x = -42)
divide both sides by negative 2 to solve for x
x =21
plug in x  into original equation to solve for y.
21 + y = 53
subtract both sides by 21
y=32



8 0
3 years ago
Help Help Help Help Help
mr Goodwill [35]

Answer:

the answer would be a I am pretty sure

4 0
3 years ago
Read 2 more answers
Choose the correct expressions using the fewest number of bases possible that are equivalent to the current expression. Select A
rjkz [21]
<h3>2 Answers: Choice B, Choice C</h3>

The rule we use here is \frac{a^b}{a^c} = a^{b-c}

If the font size is too small, then it says (a^b)/(a^c) = a^(b-c)

We subtract the exponents when dividing exponentials like this. The bases must be the same.

So this means the exponents 13 and 3 subtract to get 13-3 = 10

We either have an exponent of "13-3" or an exponent of "10" as an equivalent expression. The base stays at 2 the entire time.

6 0
3 years ago
(03.02 MC)
kotykmax [81]

Answer:

The coordinates of J are missing.  Plus, I don't see options for the conclusions.  I made an imaginary point J, which you could correct to form the proper triangle.

Step-by-step explanation:

See the attachment.  Plot all the vertices, including a corrected point J and draw the resulting triangle.  It might be that AJKL is a slightly smaller, shifted version of AGHI.  Enter the correct coordinates and then compare.

4 0
2 years ago
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