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dalvyx [7]
3 years ago
11

Ms Washington is taking an accounting class.each class is 3/4 hour long.if there are 22 classes in all how many hours will ms Wa

shington spend in class
Mathematics
2 answers:
weqwewe [10]3 years ago
8 0
 45 minutes x 22= 990, 990 divided by 60 is 16.5 hours or 16 and 1/2 hours

coldgirl [10]3 years ago
6 0
3/4 of 22 is 16.5, so 16 and a half hours.
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Https://forms.gle/jKAg2FoMP8HFPiLR7<br> Do this if you want too.
Katen [24]

Answer:

You need permission to do that.

Step-by-step explanation:

8 0
3 years ago
The computers of six faculty members in a certain department are to be replaced. Two of the faculty members have selected laptop
Anettt [7]

Answer:

a. \frac{1}{15}

b. \frac{2}{5}

c. \frac{14}{15}

d. \frac{8}{15}

Step-by-step explanation:

Given that there are two laptop machines and four desktop machines.

On a day, 2 computers to be set up.

To find:

a. probability that both selected setups are for laptop computers?

b. probability that both selected setups are desktop machines?

c. probability that at least one selected setup is for a desktop computer?

d. probability that at least one computer of each type is chosen for setup?

Solution:

Formula for probability of an event E can be observed as:

P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}

a. Favorable cases for Both the laptops to be selected = _2C_2 = 1

Total number of cases = 15

Required probability is \frac{1}{15}.

b. Favorable cases for both the desktop machines selected = _4C_2=6

Total number of cases = 15

Required probability is \frac{6}{15} = \frac{2}{5}.

c. At least one desktop:

Two cases:

1. 1 desktop and 1 laptop:

Favorable cases = _2C_1\times _4C_1 = 8

2. Both desktop:

Favorable cases = _4C_2=6

Total number of favorable cases = 8 + 6 = 14

Required probability is \frac{14}{15}.

d. 1 desktop and 1 laptop:

Favorable cases = _2C_1\times _4C_1 = 8

Total number of cases = 15

Required probability is \frac{8}{15}.

8 0
4 years ago
Which equation correctly uses the law of cosines to solve for the missing side length of trianglepqr? 62 = p2 82 – 2(p)(8)cos(39
Evgesh-ka [11]

The equation that correctly uses the law of cosines to solve for the missing side length of trianglepqr is <u>8^2 = 7^2 +11^2 - 2(7)(11) cos <P</u>

<h3>The cosine rule formula</h3>

For us to use the cosine formula, an angle must be situated between two sides of the triangle.

According to the rule;

c^2 = a^2 + b^2 - 2ab cos C

From the given diagram, if cos<P is the reference angle, then;

a = 11

b = 7

c = 8

Substiute

8^2 = 7^2 +11^2 - 2(7)(11) cos <P

Hence the equation that correctly uses the law of cosines to solve for the missing side length of trianglepqr is <u>8^2 = 7^2 +11^2 - 2(7)(11) cos <P</u>

Learn more on law of cosine here: brainly.com/question/8288607

6 0
2 years ago
What is the answer please help me no links no links
Troyanec [42]
I think it’s 32
Hope that helped XD
6 0
3 years ago
Which sentence is correct? A. B. C. D.
Pavlova-9 [17]

Answer:

what do you mean what sentence is correct give a picture

6 0
4 years ago
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