the data represents the heights of fourteen basketball players, in inches. 69, 70, 72, 72, 74, 74, 74, 75, 76, 76, 76, 77, 77, 8
Daniel [21]
If you would like to know the interquartile range of the new set and the interquartile range of the original set, you can do this using the following steps:
<span>The interquartile range is the difference between the third and the first quartiles.
The original set: </span>69, 70, 72, 72, 74, 74, 74, 75, 76, 76, 76, 77, 77, 82
Lower quartile: 72
Upper quartile: 76.25
Interquartile range: upper quartile - lower quartile = 76.25 - 72 = <span>4.25
</span>
The new set: <span>70, 72, 72, 74, 74, 74, 75, 76, 76, 76, 77, 77
</span>Lower quartile: 72.5
Upper quartile: 76
Interquartile range: upper quartile - lower quartile = 76 - 72.5 = 3.5
The correct result would be: T<span>he interquartile range of the new set would be 3.5. The interquartile range of the original set would be more than the new set.</span>
The awnser for question 5 is 4/6
There were<span> 471 </span>adult<span> and 851 </span><span>student tickets sold</span>
Answer:
The length of the room exceeds the width by 19 feet
Step-by-step explanation:
From the question, the room measures 12 yards x 204", that 12 yards x 204 inches. To determine by how many feet the length of the room exceeds the width, we will first convert both units of measurement ( yards and inches) to feet.
To convert 12 yards to feet,
1 yard = 3 feet
∴ 12 yards will be 3 × 12 feet = 36 feet
To convert 204" to feet
12" = 1 foot
∴ 204" will be 204/12 feet = 17 feet
Hence, the room measures 36 feet × 17 feet
That is, Length of the room = 36 feet
and width of the room = 17 feet
Now, to determine by how many feet the length of the room exceeds the width, we will deduct the width of the room from the length of the room, that is,
36 feet - 17 feet = 19 feet
Hence, the length of the room exceeds the width by 19 feet.
