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4 years ago

8

Emma is moving and must rent a truck. In addition to an initial fee, the rental company charges a fee of $2.50 per mile driven.

If Emma were to drive 2 miles, the total cost would be $25. Write an equation for C,C, in terms of m,m, representing the total cost of renting the truck if Emma were to drive mm miles.
PLEASE HELP MEEEEEE!!!!

2 answers:

Paladinen [302]4 years ago

6 0

Answer: I believe the answer would be C=2.50x+20

Step-by-step explanation:

dolphi86 [110]4 years ago

5 0

Answer: i think the answer is 6 hope this helps

Step-by-step explanation: multiply the divide

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3 years ago

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SOVA2 [1]

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$8\pi\text{ square cm}$

Step-by-step explanation:

Since, we know that,

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$S=2\pi rh$

Where,

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h = height,

Given,

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So, by using Pythagoras theorem,

$4^2 = (2r)^2 + h^2$ ( see in the below diagram ),

$16 = 4r^2 + h^2$

$16 - 4r^2 = h^2$

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$\frac{dS}{dr}=2\pi(r\times \frac{1}{2\sqrt{16-4r^2}}\times -8r + \sqrt{16-4r^2})$

$=2\pi(\frac{-4r^2+16-4r^2}{\sqrt{16-4r^2}})$

$=2\pi(\frac{-8r^2+16}{\sqrt{16-4r^2}})$

Again differentiating with respect to r,

$\frac{d^2S}{dt^2}=2\pi(\frac{\sqrt{16-4r^2}\times -16r + (-8r^2+16)\times \frac{1}{2\sqrt{16-4r^2}}\times -8r}{16-4r^2})$

For maximum or minimum,

$\frac{dS}{dt}=0$

$2\pi(\frac{-8r^2+16}{\sqrt{16-4r^2}})=0$

$-8r^2 + 16 = 0$

$8r^2 = 16$

$r^2 = 2$

$\implies r = \sqrt{2}$

Since, for r = √2,

$\frac{d^2S}{dt^2}=negative$

Hence, the surface area is maximum if r = √2,

And, maximum surface area,

$S = 2\pi (\sqrt{2})(\sqrt{16-8})$

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3 years ago

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yuradex [85]

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I'm pretty sure that all you need to know since this is an elementry school question.
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3 years ago

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