Question

Which table shows ordered pairs that satisfy the function y=x2+1

Answer 1

Answer:

The table in the attached figure

Step-by-step explanation:  

we have

$y=x^{2} +1$

Find the values of x and y that satisfy the equation to create a table

so

For $x=-3$

The value of y is equal to -----> $y=(-3)^{2} +1=10$

For $x=-2$

The value of y is equal to -----> $y=(-2)^{2} +1=5$

For $x=-1$

The value of y is equal to -----> $y=(-1)^{2} +1=2$

For $x=0$

The value of y is equal to -----> $y=(0)^{2} +1=1$

For $x=1$

The value of y is equal to -----> $y=(1)^{2} +1=2$

For $x=2$

The value of y is equal to -----> $y=(2)^{2} +1=5$

For $x=3$

The value of y is equal to -----> $y=(3)^{2} +1=10$

The table in the attached figure

Answer 2

I think you meant  y = x^2 + 1.  Please use " ^ " to denote exponentiation.

Since you haven't shared the table, I'll choose a few x values and find the corresponding y-values:

x   y
--  --
0   1
1   2
2   5
10 101