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hodyreva [135]
3 years ago
10

The volume of a sample of hydrogen is 771.8 mL and it exerts 638.7 mm Hg pressure at 6.5 ºC. What volume does it occupy at stand

ard temperature and pressure? Select one: a. 653 b. 2.73e4 c. 664 d. 861
Chemistry
1 answer:
slamgirl [31]3 years ago
5 0

Answer:

627mL (May be something is wrong with the choices)

Explanation:

First step: Ideal gas Law to get the moles

P . V =  n . R . T

where P is pressure in atm (638.7 mmHg)

V is volume in L

n, the number of moles, the unknow value at this time

R the Ideal gas constant 0.082 L.atm/mol.K

T, the temperature in K (°C + 273)

760 mmHg ___ 1 atm

638.7 mmHg ___ (638.7 /760) = 0.84 atm

771,8 mL / 1000 = 0.7718 L

6.5°C + 273 = 279.5 K

0.7718 L . 0.84atm = n. 0.082 L.atm/mol.K . 279.5K

0.7718 L . 0.84atm /0.082 mol.K/L.atm . 279.5K = n

0,028 moles = n

Standard temperature and pressure are 273K and 1 atm

1 atm . Volume = 0,028 moles . 0.082 L.atm/mol.K . 273K

Volume = (0,028 moles . 0.082 L.atm/mol.K . 273K) /1atm

Volume = 0,6268 L = 627mL

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A double-replacement reaction takes place when aqueous k2so4 reacts with aqueous pb(no3)2. you would expect the products of this
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A chemistry teacher adds 50.0 mL of 1.50 M H2SO4 solution to 200 mL of water. What is the concentration of the final solution? U
Aleks [24]
Hello!

The concentration of the final solution when a<span> chemistry teacher adds 50.0 mL of 1.50 M H2SO4 solution to 200 mL of water is 0,3 M

To calculate that, you'll need to use the dilution law, where initial and final concentrations are M1 and M2 respectively, and initial and final volumes are V1 and V2, as shown below. Keep in mind that the final volume is the sum of the 200 mL of water and the 50 mL of H</span>₂SO₄ that were added by the teacher. 

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Have a nice day!
6 0
3 years ago
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