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ser-zykov [4K]
3 years ago
9

A double-replacement reaction takes place when aqueous k2so4 reacts with aqueous pb(no3)2. you would expect the products of this

reaction to be ______ and _____.
Chemistry
2 answers:
SpyIntel [72]3 years ago
8 0
A double replacement is when the reactants switch with their opposite charge. For example, AB + CD = AD + BC.

In this case the given is K2SO4 + Pb(NO3)2 = ____ + ____

The answers is PbSO4 and KNO3 would expect the products of this reaction.
ella [17]3 years ago
6 0

Answer:

The products are PbSO₄ and KNO₃

Explanation:

Double replacement reaction, also called double displacement reaction is a type of reaction in which the two reactants exchange there cations or anions as represented below

AB + CD ⇒ AD + CB

The reaction provided in the question is expected to produce the products shown below

K₂SO₄ + Pb(NO₃)₂ ⇒ PbSO₄ + 2KNO₃

As you can see from the equation above, both potassium (K) in K₂SO₄ and lead (Pb) in Pb(NO₃)₂ exchanged there positions hence the reaction is a double displacement which formed PbSO₄ and KNO₃

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densk [106]

Answer:

c) hereditary

Explanation:

This means that if your parents had one eye colour, you'll most likely have the same one because you share the same genes, and it's passed down to you.

7 0
3 years ago
Read 2 more answers
A sample of xenon gas occupies a volume of 6.80 L at 52.0°C and 1.05 atm. If it is desired to increase the volume of the gas sam
Pavlova-9 [17]

Answer:

207.03°C

Explanation:

The following data were obtained from the question:

V1 (initial volume) = 6.80 L

T1 (initial temperature) = 52.0°C = 52 + 273 = 325K

P1 (initial pressure) = 1.05 atm

V2 (final volume) = 7.87 L

P2 (final pressure) = 1.34 atm

T2(final temperature) =?

Using the general gas equation P1V1/T1 = P2V2/T2, the final temperature of the gas sample can be obtained as follow:

P1V1/T1 = P2V2/T2

1.05 x 6.8/325 = 1.34 x 7.87/T2

Cross multiply to express in linear form as shown below:

1.05 x 6.8 x T2 = 325 x 1.34 x 7.87

Divide both side by 1.05 x 6.8

T2 = (325 x 1.34 x 7.87) /(1.05 x 6.8)

T2 = 480.03K

Now, let us convert 480.03K to a number in celsius scale. This is illustrated below:

°C = K - 273

°C = 480.03 - 273

°C = 207.03°C

Therefore, the final temperature of the gas will be 207.03°C

5 0
3 years ago
2. Matt went to his friend’s party. He ate a big meal and drank a keg of beer. He felt heartburn after the meal and took Tums to
evablogger [386]

Answer:

390.85mL

Explanation:

Step 1:

Data obtained from the question.

Initial pressure (P1) = 780 torr

Initial volume (V1) = 400mL

Initial temperature (T1) = 40°C = 40°C + 273 = 313K

Final temperature (T2) = 25°C = 25°C + 273 = 298K

Final pressure (P2) = 1 atm = 760torr

Final volume (V2) =?

Step 2:

Determination of the final volume i.e the volume of the gas outside Matt's body.

The volume of the gas outside Matt's body can be obtained by using the general gas equation as shown below:

P1V1/T1 = P2V2/T2

780 x 400/313 = 760 x V2 /298

Cross multiply to express in linear form

313 x 760 x V2 = 780 x 400 x 298

Divide both side by 313 x 760

V2 = (780 x 400 x 298) /(313 x 760)

V2 = 390.85mL

Therefore, the volume of the gas outside Matt's body is 390.85mL

3 0
3 years ago
What is the mass number of beryllium
kakasveta [241]

Answer:

9.012182 u

Explanation:

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What is the Kelvin temperature for 30°C? 130 K 30 K 273 K 293 K 303 K
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The answer is 303 K, to find K you have to add 273 to the °C

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