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Ganezh [65]
3 years ago
9

50cm3 of a mixture of methane and hydrogen were mixed with excess oxygen and exploded, the product after cooling to the original

room temperature were treated with excess koH solution when the volume decrease by 40cm3 , calculate the composition of the original mixture
Chemistry
1 answer:
marin [14]3 years ago
8 0

Answer:the initial composition of the reactants is

40cm^3 of CH4

40cm^3of H2

100cm^3 of H2O

Explanation:

Balanced reaction is

CH4 +H2+5/2O2______

CO2 +3H2O

Excess KOH at room temperature absorbs CO2 whose volume is given by 40cm^3 i.e the volume by which the solution decreases

So using Gay lussac combining ratio which states that gases combine in volumes that are in simple ratio to each other if gases.

Since CO2 in the equation is 1 mole

Means 1mole represent 40cm^3

So CH4:H2:O2 are in ratio of 1:1:5/2=(40:40:100)cm^3 respectively.

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2 years ago
How does the crystalline structure of a metal differ from the structure of an ionic compound, such as sodium chloride or cesium
Sergio [31]

Answer:

The metal cube lattice is made of only one kind of atom.

Explanation:

As we know that metallic crystals are made up of only one kind of element.  A metal crystal is actually a huge sea of positive charges embedded in the layers of negative charges (electrons). The whole crystal is made up of same kind of atoms, e.g crystals of gold, crystals of iron.

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7 0
3 years ago
How many kL does a 9.51 ´ 109 cL sample contain?
elena-14-01-66 [18.8K]

Answer:

9.51 × 10⁴ kL

Explanation:

Step 1: Given data

Volume of the sample (V): 9.51 × 10⁹ cL

Step 2: Convert "V" to liters

We will use the conversion factor 1 L = 100 cL.

9.51 × 10⁹ cL × (1 L / 100 cL) = 9.51 × 10⁷ L

Step 3: Convert "V" to kL

We will use the conversion factor 1 kL = 1000 L.

9.51 × 10⁷ L × (1 kL / 1000 L) = 9.51 × 10⁴ kL

9.51 × 10⁹ cL is equal to 9.51 × 10⁴ kL.

4 0
3 years ago
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