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sattari [20]
3 years ago
15

Questions 25,26 28, 29

Chemistry
2 answers:
Lady bird [3.3K]3 years ago
8 0
25. A 
26. D 
I am not sure about 28 and 29 sorry 
dybincka [34]3 years ago
3 0
I believe number 26 if in correct is product.
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Is the combination of all forces acting on an object
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What is the general trend for valence electrons as you go across the periodic table left to right
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Why do larger gases such as Neon produce more color bands (line spectra) than smaller gases like Hydrogen?
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3 years ago
How many liters of hydrogen gas are formed from the complete reaction of 1.03 mol of C? Assume that the hydrogen gas is collecte
aliina [53]

Answer:

27 liters of hydrogen gas will be formed

Explanation:

Step 1: Data given

Number of moles C = 1.03 moles

Pressure H2 = 1.0 atm

Temperature = 319 K

Step 2: The balanced equation

C +H20 → CO + H2

Step 3: Calculate moles H2

For 1 mol C we need 1 mol H2O to produce 1 mol CO an 1 mol H2

For 1.03 moles C we'll have 1.03 moles H2

Step 4: Calculate volume H2

p*V = n*R*T

⇒with p = the pressure of the H2 gas = 1.0 atm

⇒with V = the volume of H2 gas = TO BE DETERMINED

⇒with n = the number of moles H2 gas = 1.03 moles

⇒with R = the gas constant = 0.08206 L*Atm/mol*K

⇒with T = the temperature = 319 K

V = (n*R*T)/p

V = (1.03 * 0.08206 *319) / 1

V = 27 L

27 liters of hydrogen gas will be formed

8 0
2 years ago
Select the correct answer from each drop-down menu. A student labels two 250 milliliter beakers with the letters A and B. She pu
Lelechka [254]

Answer:

The solution in beaker A is unsaturated

The solution in beaker B is saturated

Explanation:

A saturated solution is a solution that contains just as much solute as it can normally hold at a particular temperature. An unsaturated solution is a solution that contains less solute than it can normally hold at a particular temperature.

If more solute is added to a saturated solution, the added solute does not dissolve completely. However, if more solute is added to an unsaturated solution, the added solute dissolves.

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