I NEED THIS NOW DILATIONS HELP ME PLS

Mathematics

1 answer:

docker41 [41]3 years ago

5 0

Answer:

reflect over the y-axis, then translate (x+(-1), y + (1))

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HELPPP PLEASEEE !!! John draws AABD, with CD as the perpendicular bisector of AB such that AACD and ABCD are congruent to each o

laila [671]

Answer:

The points on the perpendicular bisector of a side of a triangle are equidistant from the vertices of the side it bisects.

Step-by-step explanation:

It is the last option. The perpendicular bisector theorem states that if a point lies on the bisector of a segment it is equidistant from the endpoints.

Meaning

If a perpendicular bisector is a line of the side of the triangle , it bisects the sides forming two right angles .

The first three choices are incorrect because

1) the figure shows a triangle bisected into two triangles and option 1 tells about 1 isosceles triangle.

2) The base angles of any triangle can be different or same .

3) the three perpendicular bisectors meet at a point called the circumeter. We have 1 perpendicual bisector which is dividing the triangle into two equal triangles.

4 0

3 years ago

What is the maximum number of possible solutions for the system shown below?

julsineya [31]

$\bf \begin{cases} 3x^2+y^2=4\\[-0.5em] \hrulefill\\ x^2+y=5\implies \boxed{y}=5-x^2 \end{cases} \\\\\\ \stackrel{\textit{substituting \boxed{y} in the 1st equation}}{3x^2+\left( \boxed{5-x^2} \right)^2=4}\implies 3x^2+25-10x^2+x^4=4 \\\\\\ x^4-8x^2+21=0\impliedby \begin{array}{llll} \textit{the degree of this polynomial}\\ \textit{is 4, and by the fundamental}\\ \textit{theorem of algebra, it can}\\ \textit{have \boxed{4} solutions at most} \end{array}$