If<span> the degree </span>measure<span> of </span>two<span> complementary </span>angles<span> are in the ratio of </span>1<span>:14, ... These are similar to complementary </span>angles<span>, except </span>their<span> sum is </span>180<span> degrees. ... </span>1<span> = </span>angle 3<span>, (because they are vertical </span>angles<span>), </span>then<span> the </span>measure<span> of </span>angle 3<span> = y - 5.</span>
I would say the width is 7 without having a picture.
9514 1404 393
Answer:
1.63 cm (across the centerline from release)
Step-by-step explanation:
If we assume time starts counting when we release the weight from its fully-extended downward position, then the position at 1.15 seconds can be found from ...
h(t) = -7cos(2πt/4)
h(1.15) = -7cos(π·1.15/2) = -7(-0.233445) ≈ 1.63412 . . . cm
That is, 1.15 seconds after the weight is released from below the resting position, it will be 1.63 cm above the resting position.
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If it is released from <em>above</em> the resting position, it will be 1.63 cm <em>below</em> the resting position at t=1.15 seconds.
C, 125. Hope I helped.
btw, u gotta do 35+30+25+20+15