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3 years ago

How do you figure out the value of 1/10th of 20.44

Mathematics

1 answer:

KatRina [158]3 years ago

3 0

Hedge ghettos was the best way for me today was gonna you wanna come back home from home today for a

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Can someone help I know it's easy. ( picture attached)

lys-0071 [83]

Answer:

B 125.6

Step-by-step explanation:

We can use the formula for the circumference to solve.

C=2 $\pi$ r

C=2 $\pi$ (20)

C=(6.28)(20)

C=125.6

8 0

3 years ago

Which of the following is the solution to lx-13 k 18 ?

natali 33 [55]

I think d is the answer

7 0

3 years ago

Given the figure what is the value of x show your work

grandymaker [24]

51 + 3x+5 = 107

Simplify the left side:

3x + 56 = 107

Subtract 56 from both sides:

3x = 51

Divide both sides by 3:

x = 51 / 3

x = 17

Angle F and the outside angle of 107, need to equal 180 degrees.

F - 180 - 107 = 73 degrees.

5 0

3 years ago

if you roll a fair 6-sided die 9 times, what is the probability that at least 2 of the rolls come up as a 3 or a 4?

Kay [80]

Using the binomial distribution, it is found that there is a 0.857 = 85.7% probability that at least 2 of the rolls come up as a 3 or a 4.

For each die, there are only two possible outcomes, either a 3 or a 4 is rolled, or it is not. The result of a roll is independent of any other roll, hence, the <em>binomial distribution</em> is used to solve this question.

Binomial probability distribution

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.

n is the number of trials.

p is the probability of a success on a single trial.

In this problem:

There are 9 rolls, hence $n = 9$ .

Of the six sides, 2 are 3 or 4, hence $p = \frac{2}{6} = 0.3333$

The desired probability is:

$P(X \geq 2) = 1 - P(X < 2)$

In which:

$P(X < 2) = P(X = 0) + P(X = 1)$

Then

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{9,0}.(0.3333)^{0}.(0.6667)^{9} = 0.026$

$P(X = 1) = C_{9,1}.(0.3333)^{1}.(0.6667)^{8} = 0.117$

Then:

$P(X < 2) = P(X = 0) + P(X = 1) = 0.026 + 0.117 = 0.143$

$P(X \geq 2) = 1 - P(X < 2) = 1 - 0.143 = 0.857$

0.857 = 85.7% probability that at least 2 of the rolls come up as a 3 or a 4.

For more on the binomial distribution, you can check brainly.com/question/24863377

7 0

2 years ago

A distribution of values is normal with a mean of 188 and a standard deviation of 20.8. Find the probability that a randomly sel

padilas [110]

Answer:0.8413

Step-by-step explanation:

Mean= 188, Std Dev. =20.8, Z=(x-mean)/Std Dev

P(X less than 167.2)= P(Z less than (167.2-188)/20.8)

=P(Z less than (-20.8/20.8))

=P(z less than -1)= P(Z less 1)

The value of 1 in the normal distribution table is 0.3413

So we add 0.5 to 0.3413 =0.8413

6 0

3 years ago