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nirvana33 [79]
4 years ago
13

How do you figure out the value of 1/10th of 20.44

Mathematics
1 answer:
KatRina [158]4 years ago
3 0
Hedge ghettos was the best way for me today was gonna you wanna come back home from home today for a
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What is the answer to -9(4x-10)+24
melamori03 [73]

-36x + 114

Hope That Helps!

8 0
3 years ago
A picture frame is 20 inches long and 7 inches tall. It is 1 inch wide on all 4 sides. What is the area of the picture frame? 26
jek_recluse [69]

The picture's length and width are 18 and 5. You subtract 2 instead of 1 because you are subtracting 1 on both sides of the frame.

The area of the picture is 90, and the area of the whole thing, picture and picture frame, is 20*7=140.

So, to find the area of just the picture frame, you subtract 90 from 140 to get 50in^2, which is your last answer choice.

4 0
3 years ago
Ejsodndodndodjeosndi??
nalin [4]
Itxutxitxikhxkyztidurdutzktxgxkh
5 0
3 years ago
Find the probability for the experiment of tossing a coin three times. Use the sample space S = {HHH, HHT, HTH, HTT, THH, THT, T
myrzilka [38]

Answer:

1) 0.375

2) 0.375

3) 0.5

4) 0.5

5) 0.875

6) 0.5                          

Step-by-step explanation:

We are given the following in the question:

Sample space, S = {HHH, HHT, HTH, HTT, THH, THT, TTH, TTT}.

\text{Probability} = \displaystyle\frac{\text{Number of favourable outcomes}}{\text{Total number of outcomes}}

1. The probability of getting exactly one tail

P(Exactly one tail)

Favorable outcomes ={HHT, HTH, THH}

\text{P(Exactly one tail)} = \dfrac{3}{8} = 0.375

2. The probability of getting exactly two tails

P(Exactly two tail)

Favorable outcomes ={ HTT,THT, TTH}

\text{P(Exactly two tail)} = \dfrac{3}{8} = 0.375

3. The probability of getting a head on the first toss

P(head on the first toss)

Favorable outcomes ={HHH, HHT, HTH, HTT}

\text{P(head on the first toss)} = \dfrac{4}{8} = \dfrac{1}{2} = 0.5

4. The probability of getting a tail on the last toss

P(tail on the last toss)

Favorable outcomes ={HHT,HTT,THT,TTT}

\text{P(tail on the last toss)} = \dfrac{4}{8} = \dfrac{1}{2} = 0.5

5. The probability of getting at least one head

P(at least one head)

Favorable outcomes ={HHH, HHT, HTH, HTT, THH, THT, TTH}

\text{P(at least one head)} = \dfrac{7}{8} = 0.875

6. The probability of getting at least two heads

P(Exactly one tail)

Favorable outcomes ={HHH, HHT, HTH,THH}

\text{P(Exactly one tail)} = \dfrac{4}{8} = \dfrac{1}{2} = 0.5

3 0
3 years ago
|x|=14<br><img src="https://tex.z-dn.net/?f=%20%7Cx%7C%20%3D%2014" id="TexFormula1" title=" |x| = 14" alt=" |x| = 14" align="abs
Lady_Fox [76]
The absolute value of 14 could be positive 14 or -14 because an answer for absolute be positive.

So the answer could be negative 14 or positive 14 whichever one you decide to go with.
4 0
3 years ago
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