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2 years ago

What is the remainder when 6x^4-3x^5+2x^3+x-3 is divided by x+1

Mathematics

1 answer:

Svetlanka [38]2 years ago

5 0

The remainder is 3 when we need to divide $6x^4-3x^5+2x^3+x-3\,\,by \,\,x+1$

Step-by-step explanation:

We need to divide $6x^4-3x^5+2x^3+x-3\,\,by \,\,x+1$ and find the remainder

Dividing:

The division is shown in figure below:

The quotient is: $-3x^4+9x^3-7x^2+7x-6$

The remainder is: 3

So, The remainder is 3 when we need to divide $6x^4-3x^5+2x^3+x-3\,\,by \,\,x+1$

Keywords: Division of Polynomials

Learn more about Division of Polynomials at:

#learnwithBrainly

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Setler [38]

Answer:

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Step-by-step explanation:

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2 years ago

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Step-by-step explanation:

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2 years ago

A wire that is 0.20 meters long is moved perpendicularly through a magnetic field of strength 0.45 newtons/amperes meter at a sp

Natali [406]

Answer:

Given:

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Step-by-step explanation:

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2 years ago

What is the slope of the line passing through<br> points (6, -1) and (1,8)?

Fynjy0 [20]

Answer:

-1.8

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2 years ago

Z to the power of 2 =1

stiv31 [10]

That would be written as:

$z^{2} = 1$

And the step-by-step equation would be:

$z^{2} = 1$ → we take the 2 to the right side of the equation and do the IO*

$z = \sqrt{1}$ →we solve for $\sqrt{1}$

$z = 1$ → final answer

*Ps - IO is not an existing term and stands for inverse operation. In this case, because when we take to 2 to the right side of the equation (the 2 is a power) it'll have to turn into a square root (because exponents and roots are inverse operations)

Hope it helped,

BioTeacher101

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2 years ago