Question

What is the remainder when 6x^4-3x^5+2x^3+x-3 is divided by x+1

Answer 1

The remainder is 3 when we need to divide $6x^4-3x^5+2x^3+x-3\,\,by \,\,x+1$

Step-by-step explanation:

We need to divide $6x^4-3x^5+2x^3+x-3\,\,by \,\,x+1$ and find the remainder

Dividing:

The division is shown in figure below:

The quotient is:$-3x^4+9x^3-7x^2+7x-6$

The remainder is: 3

So, The remainder is 3 when we need to divide $6x^4-3x^5+2x^3+x-3\,\,by \,\,x+1$

Keywords: Division of Polynomials

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