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posledela
2 years ago
5

Find the GCF of 6 and 21 A. 126 B. 21 C. 3 D. None of the above

Mathematics
2 answers:
vladimir2022 [97]2 years ago
6 0

Answer:

C. 3

Step-by-step explanation:

6 = 2 \times 3 \\  \\ 21 = 3 \times 7 \\  \\  \because \: common \: factor = 3 \\  \\  \therefore \: gcf \: of \: 6 \: and \: 21 = 3

Marat540 [252]2 years ago
4 0

Answer:

C. 3

Step-by-step explanation:

Prime Factorization of 6:  2 × 3

Prime Factorization of 21:  3 × 7

Common Factors of 6 and 21: 3

So the greatest common factor of 6 and 21 is 3, that is, GCF of 6 and 21 is 3.

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3 years ago
Use the zero product property to find the solitions to the equation(x+2)(x+3)=12.
kykrilka [37]

Answer:

(x + 2) (x + 3) = x² + 3x + 2x + 6 = 12  (multiply the binomials)

(x + 2) (x + 3) = x² + 5x + 6 = 12

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x² + 5x + 6 = 0

Using the snowflake method -  (finding the factors of 6 that adds/subtracts to give you 5).  

This method will give you the factors (x + 6)(x - 1)

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The two solutions to the equation are -6 and 1.

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What is the equation, in point-slope form, of the line that is perpendicular to the given line and passes through the
Svetradugi [14.3K]

keeping in mind that perpendicular lines have negative reciprocal slopes, hmmmm what's the slope of that line above anyway,

\bf (\stackrel{x_1}{1}~,~\stackrel{y_1}{-1})\qquad (\stackrel{x_2}{4}~,~\stackrel{y_2}{2}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{2}-\stackrel{y1}{(-1)}}}{\underset{run} {\underset{x_2}{4}-\underset{x_1}{1}}}\implies \cfrac{2+1}{3}\implies 1 \\\\[-0.35em] ~\dotfill

\bf \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{\underline{1}\implies \cfrac{\underline{1}}{1}}\qquad \qquad \qquad \stackrel{reciprocal}{\cfrac{1}{\underline{1}}}\qquad \stackrel{negative~reciprocal}{-\cfrac{1}{\underline{1}}\implies -1}}

so we're really looking for the equation of a line whose slope is -1 and runs through (2,5)

\bf (\stackrel{x_1}{2}~,~\stackrel{y_1}{5})~\hspace{10em} \stackrel{slope}{m}\implies -1 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{5}=\stackrel{m}{-1}(x-\stackrel{x_1}{2}) \\\\\\ y-5=-x+2\implies y=-x+7

8 0
3 years ago
Read 2 more answers
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