You cant parentheses in that sentecne
Answer:
3/5
Step-by-step explanation:
Answer:
(x + 2) (x + 3) = x² + 3x + 2x + 6 = 12 (multiply the binomials)
(x + 2) (x + 3) = x² + 5x + 6 = 12
(x + 2) (x + 3) = x² + 5x + 6-12 = 0 (add the like term and bring the positive 12 to the other side which makes it negative)
x² + 5x + 6 = 0
Using the snowflake method - (finding the factors of 6 that adds/subtracts to give you 5).
This method will give you the factors (x + 6)(x - 1)
ZERO PROPERTY RULE:
(x + 6) = 0
x = -6
(x - 1) = 0
x = 1
The two solutions to the equation are -6 and 1.
Just need to find out under early to add graduate and undergraduate together and then see if how much out of the total of those who registered early is undergraduate
keeping in mind that perpendicular lines have negative reciprocal slopes, hmmmm what's the slope of that line above anyway,
![\bf (\stackrel{x_1}{1}~,~\stackrel{y_1}{-1})\qquad (\stackrel{x_2}{4}~,~\stackrel{y_2}{2}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{2}-\stackrel{y1}{(-1)}}}{\underset{run} {\underset{x_2}{4}-\underset{x_1}{1}}}\implies \cfrac{2+1}{3}\implies 1 \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=%5Cbf%20%28%5Cstackrel%7Bx_1%7D%7B1%7D~%2C~%5Cstackrel%7By_1%7D%7B-1%7D%29%5Cqquad%20%28%5Cstackrel%7Bx_2%7D%7B4%7D~%2C~%5Cstackrel%7By_2%7D%7B2%7D%29%20~%5Chfill%20%5Cstackrel%7Bslope%7D%7Bm%7D%5Cimplies%20%5Ccfrac%7B%5Cstackrel%7Brise%7D%20%7B%5Cstackrel%7By_2%7D%7B2%7D-%5Cstackrel%7By1%7D%7B%28-1%29%7D%7D%7D%7B%5Cunderset%7Brun%7D%20%7B%5Cunderset%7Bx_2%7D%7B4%7D-%5Cunderset%7Bx_1%7D%7B1%7D%7D%7D%5Cimplies%20%5Ccfrac%7B2%2B1%7D%7B3%7D%5Cimplies%201%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)
so we're really looking for the equation of a line whose slope is -1 and runs through (2,5)
