1) 110+30+a = 180
a = 180-140 = 40
Obtuse angled triangle
2) 50+50+C = 180
C=180-100 =80
Acute angled triangle
3) 45+45+b =180
b =180-90 = 90
Right angled triangle
4) 45+60+C = 180
C = 180-105 =75
Acute angled triangle
5) 94+47+b =180
b = 180-141=39
Obtuse angled triangle
6)81+53+a = 180
a =180-134 = 46
Acute angled triangle
7) 38+45+b =180
b = 180-83 =97
Obtuse angled triangle
8) 36+54+C =180
C =180-90 = 90
Right angled triangle.
Answer:
Final answer is 
Step-by-step explanation:
We need to find the equation of the line that is parallel to x=6y-5 and that passes through (5,-3).
So first we need to find the slope of given line.
rewirite x=6y-5 in y=mx+b form
x+5=6y

Compare given equation with y=mx+b
we get: m=1/6
We know that parallel equations has equal slope.
Then slope of required line m=1/6
Now plug the given point (5,-3) and slope m=1/6 into point slope formula:





Now we need to rewrite that equation in standard form. Ax+By=C.
6y=x-23
x-23=6y
x-6y=23
Hence final answer is 
Answer:
36s^3
Step-by-step explanation:
Answer:
Step-by-step explanation:
We are given the slope along with an (x, y) coordinate with which to write the equation. You could use this info in the slope-intercept form and solve for b, or you could use this info in the point-slope form and solve it for y. Trust me when I tell you that either one will get you the correct equation. Promise! I used the point-slope form, just because. ; )
y - 2 = 3(x - 1) and
y - 2 = 3x - 3 and
y = 3x - 1 OR in standard form, we will put the x and y terms on the same side of the equals sign, separated from the constant:
-3x + y = -1. But if we get picky and do not like to lead with negatives, we could change ALL the signs to their opposites (which is the same as multiplying the whole thing by a -1) to get
3x - y = 1 which is the third choice down.