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evablogger [386]
3 years ago
11

Two thermometers are calibrated, one in degrees Celsius and the other in degrees Fahrenheit.

Physics
1 answer:
pochemuha3 years ago
5 0

Answer:

temperature for which two scales are same is given as

x = - 40^oC

Explanation:

As we know that temperature scales are linear function

so we can compare two temperature scales by

\frac{T_c - T_f}{T_b - T_f} = constant

now we have

\frac{T_c - 0}{100 - 0} = \frac{T_f - 32}{212 - 32}

here we know that

T_c = T_f = x

so we have

\frac{x - 0}{100} = \frac{x - 32}{180}

1.8 x = x - 32

x = - 40^oC

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The speed of the golf ball is much greater than the speed of the bowling ball.

Explanation:

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In the future, people will only enjoy one sport: Electrodes. In this sport, you gain points when you cause metallic discs hoveri
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Answer:

  • Disk C and Disk D

Explanation:

The total charge in the disks

q_1 + q_2 = q_{total}

must be conserved before and after bringing them together.

Lets equate the sum of the initial charge with the sum of the final for the disk:

q_{1_i} + q_{2_i} = q_{1_f} + q_{2_f} = 2 * (+8.5) \mu C

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As the only positive charges are q_C and q_D, this disk must be the ones we are looking for. And, as we can see, they sum 17 μC:

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3 0
3 years ago
What is magnetic flux linkage im electromagnetic series​
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Answer:

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8 0
2 years ago
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A block of mass 10 kg and measuring 250 mm on each edge is pulled up an inclined surface on which there is a film of SAE 10W-30
Ivan

Answer:

a) 2.53 * 10^-2 m/s

b) -4.78 * 10^-2 m/s

c)  1.21 * 10^-1 m/s

Explanation:

Given data :

Mass of block = 10 kg

Measuring 250mm on each side

a) calculate the speed  when a force of 75N is applied to pull block upwards

F = f + W sin∅ ( equation for applying the force of equilibrium condition in the x axis )  ----- ( 1 )

f ( friction force )=  ( 16400v * 6.25 *10^-2) =  1025 v

F ( force applied ) = 75

W ( weight of  block ) = 10 * 9.81 = 98.1 N

∅ = 30°

input values into equation 1

V = \frac{75- (98.1*sin30^{0}) }{1025} = 2.53 * 10^-2 m/s

b) Speed when no force is applied on the block

F = f + W sin∅

F = 0

f = 1025 V

W = 98.1 N

∅ = 30°

hence V = \frac{0 - (98.1*sin30^{0}) }{1025} =  - 4.78 * 10^-2 m/s

c) when a force is applied to push block down the incline

F = f + W sin∅ ----- ( 3 )

F = 75 N

f = 1025 V

W = 98.1 N

∅ = 30°

input values into equation 3 considering the fact that the weight of the block is acting in the opposite direction

75 = 1025 V - 98.1 ( sin 30° )

V = \frac{75+( 98.1*sin30^{0})  }{1025} = 1.21 * 10^-1 m/s

5 0
3 years ago
1. Fill in the blanks. (3 pts)
Usimov [2.4K]

Answer:

a) mass

b) Newtons

c) momentum formula where p stands for momentum, m stands for mass, and v stands for velocity

Hope this helps!

4 0
3 years ago
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