Answer:
I only speak English
Explanation:
I'm sorry can you type it in English
Answer:
The displacement of the spring, as measured from equilibrium, is 0.301 m
Explanation:
Hi there!
Using Hooke´s law, we can calculate the displacement of the spring:
F = -kx
Where:
F = restoring force exerted by the spring.
k = spring constant.
x = displacement of the spring.
The force exerted by the spring can also be calculated using the Newton law:
F = m · a
Where:
F = force.
m = mass of the object.
a = acceleration.
Then, combining both laws:
F = -k · x = m · a
-k · x = m · a
-339 N/m · x = 10.0 kg · 10.2 m/s²
x = 10.0 kg · 10.2 m/s² / -339 N/m
x = -0.301 m
The displacement of the spring, as measured from equilibrium, is 0.301 m
Answer:
966.22 mph
Explanation:
Velocity of plane with respect to wind (Vp,w)= 612 mph east
velocity of wind with respect to ground, (Vw,g) = 362 mph at 15° North of
east
Write the velocities in vector form
Use the formula for the relative velocity
Where, V(p,w) is the velocity of plane with respect to wind
V(p,g) is the velocity of plane with respect to ground
V(w,g) is the velocity of wind with respect to ground
So,
Magnitude of velocity of lane with respect to ground
V(p,g) = 966.22 mph
Answer:
h = 65.021 m
Explanation:
Given that,
Initial velocity of a baseball, u = 17 m/s
It lands 2.3 seconds later.
We need to find the height of the building. Let it is h. It can be calculated using second equation of motion as follows :
here, a = g
So, the building is 65.021 m tall.
Answer:
Answer is in the picture.
Explanation:
Answer is in the picture.