Answer: TO SACRIFICE MY OWN LIFE FOR PAKISTAN
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Answer:
(C) Mass of KCl(s), mass of H20, initial temperature of the water, and final temperature of the solution
Explanation:
molar enthalpy of solution of KCl(s) is heat evolved or absorbed when one mole of KCl is dissolved in water to make pure solution . The heat evolved or absorbed can be calculated by the following relation.
Q = msΔt where m is mass of solution or water , s is specific heat and Δt is change in temperature of water .
So data required is mass of water or solution , initial and final temperature of solution , specific heat of water is known .
Now to know molar heat , we require mass of solute or KCl dissolved to know heat heat absorbed or evolved by dissolution of one mole of solute .
<h2>ingredients
:</h2>
2 ¾ cups all-purpose flour
1 teaspoon baking soda
½ teaspoon baking powder
1 cup butter, softened
1 ½ cups white sugar
1 egg
1 teaspoon vanilla extract
Explanation:
Step 1
Preheat oven to 375 degrees F (190 degrees C). In a small bowl, stir together flour, baking soda, and baking powder. Set aside.
Step 2
In a large bowl, cream together the butter and sugar until smooth. Beat in egg and vanilla. Gradually blend in the dry ingredients. Roll rounded teaspoonfuls of dough into balls, and place onto ungreased cookie sheets.
Step 3
Bake 8 to 10 minutes in the preheated oven, or until golden. Let stand on cookie sheet two minutes before removing to cool on wire racks.
Partner Tip
Reynolds® Aluminum foil can be used to keep food moist, cook it evenly, and make clean-up easier.
creds to : https://www.allrecipes.com/recipe/9870/easy-sugar-cookies/
hope you have a wonderful day :)
Answer:
127.15 g of ZnCl₂
Solution:
The balance chemical equation is as follow,
<span> Zn + 2 HCl </span>→ ZnCl₂ + H₂
According to equation,
65.38 g (1 mole) of Zn produced = 136.28 g (1 mole) of ZnCl₂
So,
61.0 g of Zn will produce = X g of ZnCl₂
Solving for X,
X = (61.0 g × 136.28 g) ÷ 65.38 g
X = 127.15 g of ZnCl₂
Answer:
Thermal energy always moves from where there is<u> more </u>of it to where there is<u> less </u>of it until <u>distributed</u>.
Explanation:
Its true, just don't know if its correct for your assignment