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Over [174]
3 years ago
14

What is the net ionic charge of an oxygen ion? a+3 b-3 c-2 d-1

Chemistry
2 answers:
neonofarm [45]3 years ago
7 0
C. -2
For future reference, the periodic table should tell you.
slava [35]3 years ago
7 0

Answer : The correct option is, (c) (-2) charge

Explanation :

For the neutral atom, the number of protons and electrons are equal. But, they are unequal when the atoms present in the form of ions or the atom has some charges.

When an unequal number of electrons and protons then it leads to the formation of ionic species.

Ion : An ion is formed when an atom looses or gains electron.

When an atom looses electrons, it will form a positive ion known as cation.

When an atom gains electrons, it will form a negative ion known as anion.

The neutral atom oxygen has equal number of protons and electrons i.e 8.

The electronic configuration of oxygen atom is:

1s^22s^22p^4

As we know that oxygen has tendency to gain 2 electrons and become stable by fully filled electronic configuration.

By gaining of 2 electrons, an oxygen will form a negative ion i.e, O^{2-}

Thus, the net ionic charge of an oxygen ion is, (-2)

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olga_2 [115]
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An electrochemical cell is composed of pure nickel and pure iron electrodes immersed in solutions of their divalent ions at room
Andrej [43]

Answer:

0.758 V.

Explanation:

Hello!

In this case, case when we include the effect of concentration on an electrochemical cell, we need to consider the Nerst equation at 25 °C:

E=E\°-\frac{0.0591}{n} log(Q)

Whereas n stands for the number of moles of transferred electrons and Q the reaction quotient relating the concentration of the oxidized species over the concentration of the reduced species. In such a way, we can write the undergoing half-reactions in the cell, considering the iron's one is reversed because it has the most positive standard potential so it tends to reduction:

Fe^{2+}+2e^-\rightarrow Fe^0\ \ \ E\°=0.440V\\\\Ni^0\rightarrow Ni^{2+}+2e^-\ \ \ E\°=-0.250V

It means that the concentration of the oxidized species is 0.002 M (that of nickel), that of the reduced species is 0.40 M and there are two moles of transferred electrons; therefore, the generated potential turns out:

E=(0.440V+0.250V)-\frac{0.0591}{2} log(\frac{0.002M}{0.40M} )\\\\E=0.758V

Beat regards!

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3 years ago
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Answer:

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Explanation:

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