Zn+2HCl=ZnCl2+H2 how many moles of ZnCl2 will be produced from 61.0 g of ZnCl2, assuming HCl is available in excess?

Chemistry

2 answers:

Sav [38]3 years ago

7 0

how did you get 136.28

docker41 [41]3 years ago

5 0

Answer:
127.15 g of ZnCl₂

Solution:
The balance chemical equation is as follow,

 Zn + 2 HCl → ZnCl₂ + H₂

According to equation,

65.38 g (1 mole) of Zn produced = 136.28 g (1 mole) of ZnCl₂
So,
61.0 g of Zn will produce = X g of ZnCl₂

Solving for X,
X = (61.0 g × 136.28 g) ÷ 65.38 g

X = 127.15 g of ZnCl₂

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evablogger [386]

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