All categories

2 years ago

What is the volume of the cylinder below?

Mathematics

1 answer:

Svetlanka [38]2 years ago

6 0

now, let's recall Cavalieri's Principle, "solids with equal altitudes and cross-sectional areas at each height, have the same volume".

so, even though this cylinder is slanted, it has the same cross-sectional area as a cylinder that's straight-up, whose altitude is h = 5, and radius r = 4.

$\bf \textit{volume of a cylinder}\\\\ V=\pi r^2 h~~ \begin{cases} h=5\\ r=4 \end{cases}\implies V=\pi (4)^2(5)\implies V=80\pi$

You might be interested in

Use the following information to determine your answer: The length of a movie falls on a normal distribution. About 95% of movie

Elenna [48]

Answer:

$75= 119 -1.96 \sigma$

$\sigma = \frac{75-119}{-1.96}= 22.45$

And tha's equivalent to use this formula:

$163= 119 +1.96 \sigma$

$\sigma = \frac{163-119}{1.96}= 22.45$

Step-by-step explanation:

For this case the 95%of the values are between the following two values:

(75 , 163)

And for this case we know that the variable of interest X "length of a movie" follows a normal distribution:

$X \sim N( \mu, \sigma)$

We can estimate the true mean with the following formula:

$\mu = \frac{75+163}{2}= 119$

Now we know that in the normal standard distribution we know that we have 95% of the values between 1.96 deviations from the mean. We can find the value of the deviation with this formula:

$75= 119 -1.96 \sigma$

$\sigma = \frac{75-119}{-1.96}= 22.45$

And tha's equivalent to use this formula:

$163= 119 +1.96 \sigma$

$\sigma = \frac{163-119}{1.96}= 22.45$

4 0

2 years ago

If one gallon of paint covers 25 sq. ft., how much paint is needed to cover 40 sq. ft.? i will mark brainliest

gogolik [260]

Answer:

1.6 gallons (so if you can only buy by the gallon, 2 gallons)

Step-by-step explanation:

You divide the total area by how much a gallon covers to get the number of gallons needed.

40/25=1.6

8 0

2 years ago

Read 2 more answers

Need help on maths question asap

Zigmanuir [339]

Answer:

276

Step-by-step explanation:

1 - 1/3 - 5/12 = 1/4

1/4 is the fraction of the vegetarian guests

1 is the total number of guests

so you multiply 69 by 4 and 276 is your answer

let me know it it is correct :)

4 0

2 years ago

What is the probability of getting a multiple of 8, in month of june?

Effectus [21]

There are 30 days in June and only three of those days are multiples of 8 so you have the probability of 3 out of 30.

3 0

2 years ago

Read 2 more answers

The local branch of the Internal Revenue Service spent an average of 21 minutes helping each of 10 people prepare their tax retu

AURORKA [14]

Answer:

The confidence Interval is [- 0.7053 10.4521]

a: The hypotheses are

H0: μ1=μ2 against the claim Ha :μ1≠μ2

b. The critical value for t∝/2 for 17 d.f t > 2.508 and t < -2.111

c. t= -2.8422

d. The calculated value of t= -2.8422 is less than t < -2.11 the critical value therefore we reject H0 and conclude there is a difference between the two means.

Step-by-step explanation:

When the standard deviations are not the same then the confidence intervals for mean differences are calculated as

(x1`-x2`)- t∝/2 √s1²/n1 + s2²/n2 < u1-u2 < (x1`-x2`)+ t∝/2 √s1²/n1 + s2²/n2

x1`= 21 x2`= 27

n1= 10 n2= 14

s1= 5.6 s2= 4.3

The degrees of freedom is calculated using

υ = [s₁²/n1 + s₂²/n2]²/ (s₁²/n1 )²/ n1-1 + (s₂²/n2)²/n2-1

= 17

The t∝/2 for 17 d.f = 2.11

Putting the values

(x1`-x2`)- t∝/2 √s1²/n1 + s2²/n2 < u1-u2 < (x1`-x2`)+ t∝/2 √s1²/n1 + s2²/n2

(21-27) - 2.11√5.6²/10+ 4.3²/14 < u1-u2 <(21-27) +2.11√5.6²/10+4.3²/14

6- 2.11*2.111 < u1-u2 < ( 6 ) +2.11*2.111

6- 4.4521 < u1-u2 < ( 6 ) +5.294

- 1.5479 < u1-u2 < 10.4521

The confidence Interval is [- 0.7053 10.4521]

a: The hypotheses are

H0: μ1=μ2 against the claim Ha :μ1≠μ2

The claim is that there is a difference in the average time spent by the two services

b. The critical value for t∝/2 for 17 d.f t > 2.508 and t < -2.111

The degrees of freedom is calculated using

υ = [s₁²/n1 + s₂²/n2]²/ (s₁²/n1 )²/ n1-1 + (s₂²/n2)²/n2-1

= 17

c. The test statistic is

t= (x1`-x2`) /√s1²/n1 + s2²/n2

t= (21-27) /√5.6²/10+ 4.3²/14

t= -6/2.111

t= -2.8422

d. The calculated value of t= -2.8422 is less than t < -2.11 the critical value therefore we reject H0 and conclude there is a difference between the two means.

5 0

2 years ago