Answer:
$11 less
Step-by-step explanation: I just did it on delta math
Answer: 84
Explanation: None
I hope this helped you, and have a good day :)
Find an equation of the plane that passes through the points p, q, and r. p(7, 2, 1), q(6, 3, 0), r(0, 0, 0)
Alona [7]
Answer:
x - 2y - 3z = 0
Step-by-step explanation:
The cross product of vectors rp and rq will give a vector that is normal to the plane:
... rp × rq = (-3, 6, 9)
Dividing this by -3 (to reduce it and make the x-coefficient positive) gives a normal vector to the plane of (1, -2, -3). Usint point r as a point on the plane, we find the constant in the formula to be zero. Hence, your equation can be written ...
... x -2y -3z = 0
Answer:
28*3(x)
Step-by-step explanation:
The product of 7 and 4 is 28.
Times a number multiplied by three is the number 28 multiplied with 3x.
SOH CAH TOA
sin is opposite/hypotenuse
cos is Adjacent/hypotenuse
tan is opposite/adjacent
