Step-by-step explanation:
The algebraic expression for The sum of z and 7 algebraic expression is given as:
z + 7
Answer:
By the Central Limit Theorem, the average value for all of the sample means is 14.
Step-by-step explanation:
We use the central limit theorem to solve this question.
The Central Limit Theorem estabilishes that, for a random variable X, with mean
and standard deviation
, the sample means of size n can be approximated to a normal distribution with mean
and standard deviation, which is also called standard error 
If the population mean is μ = 14, then what is the average value for all of the sample means?
By the Central Limit Theorem, the average value for all of the sample means is 14.
Answer:
Determination of HYP,OPP,ADJ with respect to x.
<u>Opposite</u><u> </u><u>side</u><u> </u><u>of</u><u> </u><u>right</u><u> </u><u>angle</u><u>:</u><u>Hypotenuse</u><u>:</u><u> </u><u>AC</u>
<u>Opposite</u><u> </u><u>side</u><u> </u><u>of</u><u> </u><u>given</u><u> </u><u>angle</u><u>:</u><u> </u><u>Opp</u><u>:</u><u>BC</u>
<u>remaining</u><u> </u><u>side</u><u> </u><u>of</u><u> </u><u>a</u><u> </u><u>triangle</u><u>:</u><u> </u><u>Adjacent</u><u>:</u><u>AB</u><u>.</u>
Answer:
20 hours
Step-by-step explanation:
We can work easier if we think in terms of an hour
the first equation that we can write is
A + B = 1/4 (its meaning is that in an hour A and B fill 1/4 of the cistern)
the second equation we can write is
A + C = 1/5 (its meaning is that in an hour A and C fill 1/5 of the cistern)
the third equation that we can write is
B = 2C (its meaning is that in an hour B fill 2 times C the cistern)
now we can substitute the value of B in the first two equations
A + 2C = 1/4
A + C = 1/5
A = 1/5 - C
1/5 - C + 2C = 1/4
C = 1/4 -1/5
C = (5-4)/20
C = 1/20 (this means that in an hour C will fill 1/20 of the cistern, so it takes 20 hours to fill the entire cistern)
A = 1/5 - 1/20
A = (4-1)/20 = 3/20
B = 1/20 *2 = 1/10
MrBillDoesMath!
Answer to #4: 81/256 * s^8 * t^ 12
Comments:
(7x^3) ^ (1/2) = 7 ^ (1/2) * x^(3/2) where ^(1/2) means the square root of a quantity. The answer written (7x^3) is NOT correct.
---------------------
(1) (27s^7t^11)^ (4/3)
= 27^(4/3) * (s^7)^(4/3) * (t^11)^ (4/3)
As 27 = 3^3, 27 ^(4/3) = 3^4 = 81
(2) (-64st^2)^ (4/3) = (-64)^(4/3) * (s^4/3) * t(^8/3)
As 64 = (-4)^3, (-64)^(4/3) = (-4)^4 = +256
So (1)/(2) =
81 * s^(28/3)* t^(44/3)
------------------------------- =
256 s^(4/3) * t^((8/3)
81/256 * s ^ (28/3 - 4/3) * t^(44/3 - 8/3) =
81/256 * s^(24/3) * t (36/3) =
81/256 * s^8 * t^ 12
MrB