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3 years ago

A rectangle painting is 4 feet high and 3 feet wide what is its perimeter

Mathematics

1 answer:

monitta3 years ago

7 0

Answer:

Step-by-step explanation:

To find the perimeter of a rectangle, you need to find the sum of 2 times the width and the height. 2*3+2*4=6+8=14 feet. Hope this helps!

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7. Let f(x) = 3x and g(x) = (x + 2)^2. Find the value of (f og)(-5)

Keith_Richards [23]

Answer:

plz mark brainliest

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3 0

3 years ago

10. An arithmetic sequence has this recursive formula. What is the explicit formula?

Mrrafil [7]

Answer:

$a_{n}=45-3n$

Step-by-step explanation:

Method 1:

Arithmetic sequence is in the form

$a_{n} =a_{1} +(n-1)d\\$

d is the common difference, can be found by:

$d=a_{n}-a_{n-1}=-3$

Subtituting the $a_{1}$ and $d$

You get:

$a_{n}=42+(-3)(n-1)=45-3n$

Method 2 (Mathematical induction):

Assume it is in form $a_{n}=45-3n$

Base step: $a_{1} =45-3(1)=42$

Inducive hypophesis: $a_{n}=45-3n$

GIven: $a_{n+1} =a_{n}-3$

$a_{n+1}=45-3n-3=45-3(n+1)$

Proved by mathematical induction

$a_{n}=45-3n$

5 0

3 years ago

Food Mart<br>job<br>Tuesday to Friday<br>Pay: £56 for each day in pounds

AURORKA [14]

You do 4 x 56 = 224. It’s just multiplication.

4 0

3 years ago

Read 2 more answers

All the fourth-graders in a certain elementary school took a standardized test. A total of 85% of the students were found to be

Aneli [31]

Answer:

There is a 2% probability that the student is proficient in neither reading nor mathematics.

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that a student is proficient in reading

B is the probability that a student is proficient in mathematics.

C is the probability that a student is proficient in neither reading nor mathematics.

We have that:

$A = a + (A \cap B)$

In which a is the probability that a student is proficient in reading but not mathematics and $A \cap B$ is the probability that a student is proficient in both reading and mathematics.

By the same logic, we have that:

$B = b + (A \cap B)$

Either a student in proficient in at least one of reading or mathematics, or a student is proficient in neither of those. The sum of the probabilities of these events is decimal 1. So

$(A \cup B) + C = 1$