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OLEGan [10]
3 years ago
14

Ruby uses 1/4 yard of ribbon to make 2 Bows. Which expression shows the length of ribbon in each bow ?

Mathematics
1 answer:
Oksana_A [137]3 years ago
4 0
1/4 divided by 2. Hopefully this helped!!
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Suppose that one wishes to schedule vehicles from a central depot to five customer locations. The distance of making trips betwe
sladkih [1.3K]

Answer:

The routing suggested by the savings method is route (3,4)

Step-by-step explanation:

Savings for all trips (i, j), 1 ≤ i ∠ j ≤ 5

Total  number of trips to be commuted = 10 trips

S₁₂ = C₀₁ + C₀₂ - C₁₂ = 20 + 75 - 35 = 60

S₁₃ = C₀₁ + C₀₃ - C₁₃ = 20 + 33 - 5 = 48

S₁₄ = C₀₁ + C₀₄ - C₁₄ = 20 + 10 - 20 = 10

S₁₅ = C₀₁ + C₀₅ - C₁₅ = 20 + 30 - 15 = 35

S₂₃ = C₀₂ + C₀₃ - C₂₃ = 75 + 33 - 18 = 90

S₂₄ = C₀₂ + C₀₄ - C₂₄ = 75 + 10 - 58 = 27

S₂₅ = C₀₂ + C₀₅ - C₂₅ = 75 + 30 - 42 = 63

S₃₄ = C₀₃ + C₀₄ - C₃₄ = 33 + 10 - 40 = 3

S₃₅ = C₀₃ + C₀₅ - C₃₅ = 33 + 30 - 20 = 43

S₄₅= C₀₄ + C₀₅ - C₄₅ = 10 + 30 - 25 = 15

3 0
3 years ago
How do you estimate products
luda_lava [24]

Answer:

to estimate the result of multiplication (product), round the numbers to some close numbers that you can easily multiply mentally. One method of estimation is to round all factors to the biggest digit (place value) they have.

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
In the function f(x)=6x^2-4, what is the value of f(-2)?
BartSMP [9]

In order to find the value of f(-2), you can plug -2 wherever x is.

f(x) = 6x^2 - 4

f(-2) = 6(-2)^2 - 4

f(-2) = 6(4) - 4

f(-2) = 24 - 4

f(-2) = 20

Thus, the value of f(-2) is 20. Hope this helps! If you have any other questions related to this, let me know.

4 0
3 years ago
Bert’s cab company charges $1.00 plus an additional $3.00 per mile for a ride. Madeline’s cab company charges $3.00 plus an addi
katrin [286]

Answer:

20 miles

Step-by-step explanation:

5 0
3 years ago
Integrate Sec (4x - 1) Tan (4x - 1) Dx ​
Delicious77 [7]

\bf \displaystyle\int~sec(4x-1)tan(4x-1)dx \\\\[-0.35em] ~\dotfill\\\\ sec(4x-1)tan(4x-1)\implies \cfrac{1}{cos(4x-1)}\cdot \cfrac{sin(4x-1)}{cos(4x-1)}\implies \cfrac{sin(4x-1)}{cos^2(4x-1)} \\\\[-0.35em] ~\dotfill\\\\ \displaystyle\int~\cfrac{sin(4x-1)}{cos^2(4x-1)}dx \\\\[-0.35em] ~\dotfill\\\\ u=cos(4x-1)\implies \cfrac{du}{dx}=-sin(4x-1)\cdot 4\implies \cfrac{du}{-4sin(4x-1)}=dx \\\\[-0.35em] ~\dotfill

\bf \displaystyle\int~\cfrac{~~\begin{matrix} sin(4x-1) \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~ }{u^2}\cdot \cfrac{du}{-4~~\begin{matrix} sin(4x-1) \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}\implies -\cfrac{1}{4}\int\cfrac{1}{u^2}du\implies -\cfrac{1}{4}\int u^{-2}du \\\\\\ -\cfrac{1}{4}\cdot \cfrac{u^{-2+1}}{-1}\implies \cfrac{1}{4}\cdot u^{-1}\implies \cfrac{1}{4u}\implies \cfrac{1}{4cos(4x+1)}+C

5 0
4 years ago
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