Answer:
2.7 litres of solution
Step-by-step explanation:
Answer:
cos(θ) > 0
Step-by-step explanation:
In Quadrant IV, the cosine is positive.
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In the attached, trig functions not listed are negative.
<h3>Option B</h3><h3>At 2 second and 1.75 second, the object be at a height of 56 feet</h3>
<em><u>Solution:</u></em>
Given that,
<em><u>The height h(t) in feet of an object t seconds after it is propelled straight up from the ground with an initial velocity of 60 feet per second is modeled by the equation:</u></em>

<em><u>At what times will the object be at a height of 56 feet</u></em>
<em><u>Substitute h = 56</u></em>

Solve the above equation by quadratic formula


Thus, at 2 second and 1.75 second, the object be at a height of 56 feet
X=15
Y=3
2(15)=30
3(3)=9
30+9=39
Answer:
w = 3
Step-by-step explanation:
1/w = 1 2/3 / 5 cross multiply
1 2/3 (w) = 5
w = 5 / ( 1 2/3 ) = 5 / ( 5/3) = 15/5 = 3