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Charra [1.4K]
3 years ago
5

It is not a function because both (2, 2) and (2,−2) have the same x-coordinate. It is a function because both (2, 2) and (2,−2)

have the same x-coordinate. It is not a function because for each x-coordinate, there is exactly one y-coordinate. It is a function because for each x-coordinate, there is exactly one y-coordinate.
Mathematics
1 answer:
olya-2409 [2.1K]3 years ago
3 0

Answer:

It is not a function because both (2,2) and (2,-2) have the same x-coordinate.

Step-by-step explanation:

To be a function for the same x value there should NOT be two different y values.

So, in (2, 2) and (2,-2)

For the same x value 2, there are two different y values 2, -2.

So, this is not a function.

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Answer:

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Step-by-step explanation:

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3 years ago
If sin 0 = -<br> and 270º &lt; 0&lt; 360°, what is cos 0?
Alik [6]

Answer:

  cos(θ) > 0

Step-by-step explanation:

In Quadrant IV, the cosine is positive.

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In the attached, trig functions not listed are negative.

7 0
3 years ago
GRAVITATION The height h(t) in feet of an object t seconds after it is propelled straight up from the ground with an initial vel
zhuklara [117]
<h3>Option B</h3><h3>At 2 second and 1.75 second, the object be at a height of 56 feet</h3>

<em><u>Solution:</u></em>

Given that,

<em><u>The height h(t) in feet of an object t seconds after it is propelled straight up from the ground with an initial velocity of 60 feet per second is modeled by the equation:</u></em>

h(t) = -16t^2 + 60t

<em><u>At what times will the object be at a height of 56 feet</u></em>

<em><u>Substitute h = 56</u></em>

56 = -16t^2 + 60t\\\\16t^2 - 60t + 56 = 0\\\\Divide\ the\ equation\ by\ 4\\\\4t^2 - 15t + 14=0

Solve the above equation by quadratic formula

\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

\mathrm{For\:}\quad a=4,\:b=-15,\:c=14\\\\x =\frac{-\left(-15\right)\pm \sqrt{\left(-15\right)^2-4\cdot \:4\cdot \:14}}{2\cdot \:4}\\\\Simplify\\\\x = \frac{15 \pm \sqrt{1}}{8}\\\\x = \frac{15 \pm 1}{8}\\\\We\ have\ two\ solutions\\\\x = \frac{15+1}{8} \text{ and } x = \frac{15-1}{8}\\\\x = 2 \text{ and } 1.75

Thus, at 2 second and 1.75 second, the object be at a height of 56 feet

5 0
4 years ago
2x + 3y= 39 <br><br> solve fir both x anddd y
Readme [11.4K]
X=15
Y=3

2(15)=30
3(3)=9
30+9=39
6 0
3 years ago
If 1:w is equivalent to 1⅔: 5, find w.​
sergij07 [2.7K]

Answer:

w = 3

Step-by-step explanation:

1/w = 1 2/3 / 5      cross multiply

1 2/3 (w) = 5

w = 5 / ( 1 2/3 ) =  5 / ( 5/3) = 15/5 = 3

5 0
2 years ago
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