Question

16 min left need help asap

Answer 1

Answer: XD < XY

Step-by-step explanation:

Since, By the exterior angle property,

$\angle DXY + \angle DYX = 98^{\circ}$

Since, given, $\angle DXY = 46^{\circ}$

Therefore, $46^{\circ} + \angle DYX = 98^{\circ}$

$\angle DYX = 52^{\circ}$

Now, $\angle YDX = 180^{\circ}-98^{\circ}= 82^{\circ}$ ( by the property of linear angles )

Thus,  $\angle DYX < \angle YDX$

Since, In a triangle, the opposite side of largest angle is always greater than that of smallest angle.

⇒ XD < XY

Hence, Option C is correct.