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Mathematics

1 answer:

Ainat [17]3 years ago

8 0

Answer: XD < XY

Step-by-step explanation:

Since, By the exterior angle property,

$\angle DXY + \angle DYX = 98^{\circ}$

Since, given, $\angle DXY = 46^{\circ}$

Therefore, $46^{\circ} + \angle DYX = 98^{\circ}$

$\angle DYX = 52^{\circ}$

Now, $\angle YDX = 180^{\circ}-98^{\circ}= 82^{\circ}$ ( by the property of linear angles )

Thus, $\angle DYX < \angle YDX$

Since, In a triangle, the opposite side of largest angle is always greater than that of smallest angle.

⇒ XD < XY

Hence, Option C is correct.

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