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r-ruslan [8.4K]
3 years ago
15

Evaluate 0.53n+5 when n=3 and when n=-3

Mathematics
2 answers:
melomori [17]3 years ago
4 0
<span>0.53(3)+5 = 1.59 + 5 = 6.59 when n = 3
</span>0.53(-3)+5 = -1.59 + 5 = 3.41 when n = -3
padilas [110]3 years ago
3 0
Simple...

you have: 0.53n+5

n=3

and 

n=-3

When n=3-->>

0.53(3)+5

1.59+5=6.59

When n=-3...

0.53(-3)+5

-1.59+5=3.41

Thus, your answer.
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Since this equation defines a hyperbola, we expect the asymptotes to be lines of the form p(x)=ax+b.

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\displaystyle\lim_{x\to-\infty}(2x-1+2\sqrt{x^2-x}-ax-b)=0

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Step-by-step explanation:


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