Answer:
So the surface area consists of 2 triangles and 3 different rectangles
Triangle area = 1/2 * 8cm * 6cm = 24cm²
Rectangle a area (bottom one) = 17cm * 8cm = 136cm²
Rectangle b area (the one to the left) = 17cm * 6cm = 102cm²
To calculate Rectangle c we need to know the hypotenuse of our triangles
Formula for the hypotenuse is c = ![\sqrt{a^2+b^2}](https://tex.z-dn.net/?f=%5Csqrt%7Ba%5E2%2Bb%5E2%7D)
so c =
= 10
Rectangle c area = 17cm * 10cm = 170cm²
So the surface area is 2 * 24cm² + 136cm² + 102cm² + 170cm² = 456cm²
The volume is 1/2 * h * a * b = 1/2 * 6cm * 8cm * 17cm = 408cm³
-3y-8x+3x^2 is the simplified version of 7y+2x-10y+3x^2-10x
Answer: 235 would be the estimate