Question

A second number is 7 less than the first number. The third number is twice the first number. If the sum of the three numbers is 321, find the numbers

Answer 1

Answer:

x=4

Step-by-step explanation:

hope it will help

First no.=x

2nd no.=2x

3rd no. =2x+6

x+2x+2x+6=26

5x+6=26

5×=26-6

5x =20.......divide both sides by 5

x=4

1st no.=x=4