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sineoko [7]
3 years ago
13

Expand the expression (p+4q)3(p+4q)^3 (p+4q) 3 left parenthesis, p, plus, 4, q, right parenthesis, cubed using the binomial theo

rem.
Mathematics
1 answer:
Korvikt [17]3 years ago
3 0

Answer:

p^3 + 12(p^2)q + 48p(q^2) + 64(q^3)

Step-by-step explanation:

(p+4q)^3  -->

(3C3)(p^3) + (3C2)(p^2)(4q) + (3C1)(p)(4q)^2 + (3C0)(4q)^3 =

p^3 + 12(p^2)q + 48p(q^2) + 64(q^3)

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The mali empire of west africa was known far and wide for the great wealth of its rulers. The empire fell in the year 1610161016
S_A_V [24]

We are given: The year of the empire fell = 1610.

We have x as a variable that represents the year after the given year 1610.

According to problem, the year after the year number 1610 will have a number  that greater than 1610.

We can make a statement for inequality to be written.

"The year after the 1610 is greater than 1610".

The year after the 1610 is x and we use gerater than symbol  >.

So, we can setup an inequality as:

x > 1610 : It can be read as x is greater than 1610.


4 0
3 years ago
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Why are there 27 cubic feet in one cubic yard
kobusy [5.1K]

One cubic yard is equal to 27 cubic feet because one yard is equal to 3 feet

<em><u>Solution:</u></em>

Given that, there 27 cubic feet in one cubic yard

Yard and feet are units of distance

1 Yard (yd) is equal to 3 feet (ft). To convert yards to feet, multiply the yard value by 3.

<em><u>The conversion factor for 1 yard to 1 feet is given as:</u></em>

1 \text{ yard } = 3 \text{ foot }

Now find for 1 cubic yard . Cubic yard means yard raised to power 3

Therefore,

1\ yard^3 = (3)^3\ feet^3\\\\1\ yard^3 = 27 feet^3\\\\1\ cubic\ yard = 27\ cubic\ feet

Thus one cubic yard is equal to 27 cubic feet

Therefore, there are 27 cubic feet in one cubic feet

8 0
3 years ago
Geometry Question find the area of the circle
olasank [31]
Formula for the area of a circle is Pi*radius squared
So, we do Pi*2^2 which is 12.57
8 0
3 years ago
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There is another equation that describes the path of your fruit or vegetable. This equation is: y=-16t^2+v0t+6 .
Rudiy27

Answer:

The equations have the same mathematical form:

S = A + V0 t - 1/2 g t^2

They are both quadratic equations in one variable (t here)

This equation expresses the distance traveled by an object in time t in the vertical direction  - it does not necessarily refer to a graph

In the other equation, y can be considered a vertical coordinate equation on a graph and x would be the horizontal coordinate

Note that in one equation 3 terms are necessary to describe the displacement of an object in one direction

In the other 2 terms in the x-direction describe the displacement in the other or y-direction

6 0
3 years ago
What are the coordinates of its image, J'KL, if this
shtirl [24]

Answer:

J'(-15,10)\\\\K'(15,10)\\\\L'(0,-20)

Step-by-step explanation:

For this exercise you must remember that the original figure (before a transformation) is called "Pre-Image" and the one obtained after the transformation is called "Image".

 Dilation is defined as a transformation in which the Image and the Pre-Image have the same shape, but different sizes.

If a figure is dilated by a scale factor "k" with respect to the origin, the rule is:

(x,y) → (kx,ky)

In this case, the vertices of the triangle JKL (the Pre-Image) are:

J(-3.2)\\\\K(3,2)\\\\L(0,-4)

Knowing that the scale factor is:

k=5

You get that the vertices of the triangle J'K'L' (Image), are:

J'=(5(-3),5(2))=(-15,10)\\\\K'=(5(3),5(2))=(15,10)\\\\L'=(5(0),5(-4))=(0,-20)

7 0
3 years ago
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