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4 years ago

egment AB falls on line 2x − 4y = 8. Segment CD falls on line 4x + 2y = 8. What is true about segments AB and CD?

Mathematics

1 answer:

jolli1 [7]4 years ago

8 0

Answer:

The line segments AB and CD are perpendicular to each other.

Step-by-step explanation:

Segment AB falls on line 2x − 4y = 8.

Rearranging the equation into slope-intercept form we get, ............. (1)

Therefore, slope of the line segment AB is

Now, the segment CD falls on line 4x + 2y = 8.

Rearranging the equation into slope-intercept form we get, ............. (2)

Therefore, the slope of the line segment CD is, N = - 2

So, M × N =

Hence, we can conclude that the line segments AB and CD are perpendicular to each other

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4 years ago

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3 years ago

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nadya68 [22]

Given,

HK is the perpendicular bisector of GJ. So, GK = KJ.
GK = 2x + 10
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Find KJ .

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First find the value of x

$\sf \: GK \: = KJ \\\sf 2x + 10 = 3x - 15 \\\sf 2x - 3x = - 15 - 10 \\ \sf - x = - 25 \\ \sf \: - > \boxed{\bf \: x = 25}$

Now, find the value of KJ.

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-> The value of KJ is 60.

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3 years ago

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Do the three points lie on one line?

padilas [110]

Answer:

Yes. No graph paper.

Step-by-step explanation:

Let's say the 3 points are A, B, C.

If A, B and C lie on one line then $m_{AB} = m_{BC} = m_{AC}$

$m_{AB} = \frac{y_{B}-y_{A} }{x_{B}-x_{A}} = \frac{2-6}{3-5} = \frac{-4}{-2} = 2\\m_{BC} = \frac{y_{C}-y_{B} }{x_{C}-x_{B}} = \frac{8-2}{6-3} = \frac{6}{3} = 2\\\\m_{AC} = \frac{y_{C}-y_{A} }{x_{C}-x_{A}} = \frac{8-6}{6-5} = \frac{2}{1} = 2\\\\$

Hence, they lie on one line.

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2 years ago