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3 years ago

If you bought a stock last year for a price of $98, and it has gone down 17% since

Mathematics

2 answers:

Leokris [45]3 years ago

5 0

98 - 0.17(98)

98 - 16.66

81.34

The stock is now worth $81.34.

Hope this helps!! :)

Leokris [45]3 years ago

3 0

The answer is 81.34 hope it helps

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2 years ago

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3 years ago

7/30+9/20 what is the answer pls hurry im so confused

Svetradugi [14.3K]

Here is your answer:

$\frac{7}{30} + \frac{9}{20}$
Find common denominator:
$30 \times 20 = 60 /20 \times 30 = 60$
Common denominator is 60:
$\frac{7}{30} + \frac{9}{20} = \frac{140}{60} + \frac{270}{60}$
$140 + 270 = 410$
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2 years ago

A factory uses 1/6 of a barrel of raisins in each batch of granola bars. Yesterday, the factory used 1/2 of a barrel of raisins.

balu736 [363]

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if the factory used 1/2, the factory used 3/6 of a barrel, which equals to 3 batches.

<em>hope it helps :)</em>

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2 years ago

How is the series 5+11+17…+251 represented in summation notation?

NISA [10]

Answer:

$\displaystyle \large{\sum_{n=1}^{42}(6n-1)$

Step-by-step explanation:

Given:

Series 5+11+17+...+251

To find:

Summation notation of the given series

Summation Notation:

$\displaystyle \large{\sum_{k=1}^n a_k}$

Where n is the number of terms and $\displaystyle \large{a_k}$ is general term.

First, determine what kind of series it is, there are two main series that everyone should know:

Arithmetic Series

A series that has common difference.

Geometric Series

A series that has common ratio.

If you notice and keep subtracting the next term with previous term:

11-5 = 6
17-11 = 6

Two common difference, we can in fact say that the series is arithmetic one. Since we know the type of series, we have to find the number of terms.

Now that brings us to arithmetic sequence, we know that first term is 5 and last term is 251, we’ll be finding both general term and number of term using arithmetic sequence:

<u>Arithmetic Sequence</u>

$\displaystyle \large{a_n=a_1+(n-1)d}$

Where $\displaystyle \large{a_n}$ is the nth term, $\displaystyle \large{a_1}$ is the first term and $\displaystyle \large{d}$ is the common difference:

So for our general term:

$\displaystyle \large{a_n=5+(n-1)6}\\\displaystyle \large{a_n=5+6n-6}\\\displaystyle \large{a_n=6n-1}$

And for number of terms, substitute $\displaystyle \large{a_n}$ = 251 and solve for n:

$\displaystyle \large{251=6n-1}\\\displaystyle \large{252=6n}\\\displaystyle \large{n=42}$

Now we can convert the series to summation notation as given the formula above, substitute as we get:

$\displaystyle \large{\sum_{n=1}^{42}(6n-1)$

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2 years ago