3 years ago

PLEASE I NEED HELP I ONLY HAVE 3 MINUTES TO SOLVE THIS PLEASE HELP

Mathematics

1 answer:

defon3 years ago

8 0

Answer:

A&B

Step-by-step explanation:

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c= 0 m=6

Step-by-step explanation:

0x2= 0

3x6=18

18+0=18$

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3 years ago

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what may be true

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Division facts for 2,5,10

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3 years ago

A game of chance involves rolling an unevenly balanced 4-sided die. The probability that a roll comes up 1 is 0.22, the probabil

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Answer:

Expected Winnings = 2.6

Step-by-step explanation:

Since the probability of rolling a 1 is 0.22 and the probability of rolling either a 1 or a 2 is 0.42, the probability of rolling only a 2 can be determined as:

$P_{1,2} = P_{1}+P_{2}\\P_{2} = 0.42 - 0.22 = 0.20$

The same logic can be applied to find the probability of rolling a 3

$P_{2,3} = P_{2}+P_{3}\\P_{3} = 0.54 - 0.20 = 0.34$

The sum of all probabilities must equal 1.00, so the probability of rolling a 4 is:

$P_{4} =1- P_{1}+P_{2}+P_{3} = 1-0.22+0.20+0.34\\P_{4}=0.24$

The expected winnings (EW) is found by adding the product of each value by its likelihood:

$EW=1*P_{1}+2*P_{2}+ 3*P_{3}+ 4*P_{4} \\EW=1*0.22+2*0.20+ 3*0.34+ 4*0.24\\EW=2.6$

Expected Winnings = 2.6

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3 years ago

Suppose that two fair dice are rolled. find the probability that the number on the first die is a 1 or the number on the second

Bogdan [553]

Answer:

1/36

Step-by-step explanation:

Assuming the dice has 6 sides in total, we can set up a probability for each scenario.

The chances of the dice landing on 1 will be 1/6, since there are 6 total faces. Same goes for the second die and landing on 4.

Now that we have our 2 probabilities, we multiply them to get the final probability. 1/6 x 1/6 = 1/36.

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2 years ago