Answer:
39% decrease
Step-by-step explanation:
Answer:
a) the probability of winning A and B is 0.4 (40%)
b) the probability of not winning either project is 0.1 (10%)
Step-by-step explanation:
if 2 events are independent then
P(A∩B)=P(A)*P(B)
where
P(A)= probability of winning project A
P(B)= probability of winning project B
P(A∩B)= probability of winning projects A and B
replacing values
P(A∩B)=P(A)*P(B) = 0.50 * 0.8 = 0.4
b) since
P(A∪B) = P(A) + P(B) - P(A∩B) = 0.50 + 0.8 - 0.4 = 0.9
where
P(A∪B) = probability of winning A or B
therefore
probability of not winning either project = 1 - P(A∪B) = 1 - 0.9 = 0.1 (10%)
Answer:
= 2(1 - 2h)
Step-by-step explanation:
Given that:
=3(2−0.9h)+(−1.3h−4)
Simplifying:
=(6 - 2.7h) + (-1.3h - 4)
Removing brackets
=6 - 2.7h -1.3h - 4
Adding like terms (h terms and constants)
= 2 - 4h
We can take 2 common as:
= 2(1 - 2h) Required sum
I hope it will help you!
Can you send me a picture of the question and graph?
If I had to guesstimate, the answer would be b
