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3 years ago

How do I do this?? I need help

Mathematics

2 answers:

belka [17]3 years ago

7 0

25-x=10 x= 15 25-15=10
2x+4(greater than)5 to the 2nd power. X= 15 2*15+4(greater than) 5 to the 2nd power
60-4x(less than)1. x=15 60-4*15(less than)1
5(x+5)=100. x= 15 5*(15+5)=100

NemiM [27]3 years ago

6 0

X=15

1:25-10=X X=15

2:12+X=24 X=12

3:X>=10.5

4:59<4X X>14.75

5: 15

SO JUST 1 AND 5 ARE X=15

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36.90 as a fraction what dose it equals

Soloha48 [4]

Hello!

I believe that 36.90 as a fraction would be 369/10

I hope this helps!

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2 years ago

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Steve sells half of his comic books and then buys 6 more now he has 14 comic books

ddd [48]

Let b be the initial amount of books. Steve sells half of his books, so the number of Steve's books become

$b \to \dfrac{b}{2}$

Then, he buys 6 more, so the number increases by 6:

$\dfrac{b}{2} \to \dfrac{b}{2}+6$

This number is now 14, so you have

$\dfrac{b}{2}+6 = 14$

Subtract 6 from both sides:

$\dfrac{b}{2} = 8$

Multiply both sides by 2:

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2 years ago

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Slope of -3 and y intercept 7 in slope-intercept form.

RUDIKE [14]

Y = mx + b, m = slope and b = y-intercept

Thus the answer is y = -3x + 7

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3 years ago

Laura is baking a cake. The recipe says that she has to mix 64 grams of chocolate powder to the flour. Laura knows that 1 cup of

pickupchik [31]

The answer is She went over by one over six of a cup

1 cup of that particular chocolate powder has a mass of 128 grams: 1c = 128g

64 grams of chocolate powder is x cups.
1c = 128g
x = 64g

1c : 128 g = x : 64g
x = 1c : 128 g * 64 g
x = 0.5 c
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She added two over three of a cup of chocolate powder: 2/3 cups

She need to add 1/2 cups: 1/2 = 3/6 cups
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So she added 4/6 - 3/6 = 1/6 cups more.

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3 years ago

Let f (x) = 1/x and g(x) = x² – 3x. What two numbers are not in the domain of fºg?

iren [92.7K]

For this case we have the following equations:

$f (x) = \frac {1} {x}\\g (x) = x ^ 2-3x$

We must find $(f_ {o} g) (x):$

By definition of composition of functions we have to:

$(f_ {o} g) (x) = f (g (x))$

So:

$(f_ {o} g) (x) = \frac {1} {x ^ 2-3x}$

We must find the domain of f (g (x)). The domain will be given by the values for which the function is defined, that is, when the denominator is nonzero.

$x ^ 2-3x = 0\\x (x-3) = 0$

So, the roots are:

$x_ {1} = 0\\x_ {2} = 3$

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x other than 0 and 3

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3 years ago

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