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3 years ago

How do I do this?? I need help

Mathematics

2 answers:

belka [17]3 years ago

7 0

25-x=10 x= 15 25-15=10
2x+4(greater than)5 to the 2nd power. X= 15 2*15+4(greater than) 5 to the 2nd power
60-4x(less than)1. x=15 60-4*15(less than)1
5(x+5)=100. x= 15 5*(15+5)=100

NemiM [27]3 years ago

6 0

X=15

1:25-10=X X=15

2:12+X=24 X=12

3:X>=10.5

4:59<4X X>14.75

5: 15

SO JUST 1 AND 5 ARE X=15

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6/x-8=2/x+6 how do i solve this

lutik1710 [3]

6/(x-8)=2/(x+6)
times both sides by (x-8)(x+6)
6(x+6)=2(x-8)
distribute
6x+36=2x-16
minus 2x both sides
4x+36=-16
miinus 36 both sides
4x=-52
divide both sides by 4
x=-13

8 0

4 years ago

Help help help math math

Step2247 [10]

Answer:

15cm^3

Step-by-step explanation:

1^2=1

1*3=3

3*5=15

5 0

2 years ago

Read 2 more answers

PLEASE HELP ME! <3

kotegsom [21]

Answer:

B) t can be any whole number where 0 ≤ t < 75.

Step-by-step explanation:

Edge

4 0

3 years ago

Solve the system of equations y = 40x2 and y = 19x + 3 algebraically.

ikadub [295]

We have been given a system of nonlinear equations.

$\\y=40x^{2},y=19x+3$

In order to solve this system we can first equate the two equations in order to get a quadratic in x.

$\\40x^{2}=19x+3$

Our next step is to bring all the terms on one side.

$\\40x^{2}-19x-3=0$

Now we have to solve this equation. We can solve it by factoring using the splitting middle term method.

$\\40x^{2}-24x+5x-3=0$

$\\8x(5x-3)+(5x-3)=0$

$\\(8x+1)(5x-3)=0$

Upon setting each of these factors equal to zero using zero product property we get

$\\8x+1=0 \text{ or } 5x-3 = 0$

Upon solving both these equations we get

$\\x=-\frac{1}{8} \text{ or } x=\frac{3}{5}$

Now we can substitute these values of x in the equation

$y=19x+3$

We get

$\text{For }x=- \frac{1}{8} \Rightarrow y=19(- \frac{1}{8})+3= \frac{5}{8}\\$

$\text{For }x= \frac{3}{5}\Rightarrow y=19( \frac{3}{5})+3= \frac{72}{5}\\$

Therefore, our final set of solutions are

$(x,y)=(- \frac{1}{8},\frac{5}{8}) \text{ and } ( \frac{3}{5}, \frac{72}{5})$

6 0

3 years ago

Read 2 more answers

How does the graph of g(x) = (x − 2)3 + 6 compare to the parent function of f(x) = x3?

marta [7]

The relationship of the graph g(x) = (x − 2)^3 + 6 compare to the parent function of f(x) = x^3 is that g(x) is shifted 2 units to the right and 6 units up.

<h3>Translation of coordinates</h3>

Translations is a transformation technique that changes the position of an object from one point on the plane to another.

Given the function below

g(x) = (x − 2)^3 + 6

The function compared to f(x) = x^3, shows a translation of f(x) by 2 unit to the right along the horizontal and vertical translation of the function 6 units up

Hence the relationship of the graph g(x) = (x − 2)^3 + 6 compare to the parent function of f(x) = x^3 is that g(x) is shifted 2 units to the right and 6 units up.

Learn more on translation here: brainly.com/question/12861087

#SPJ1

6 0

2 years ago