Remark
A kite is constructed such that AB = BC and AD = DC. AB = sqrt( (1/2)AC + 18^2) see diagram. AD = sqrt(24^2 + 32^2)
Step One
Solve for AB
1/2 AC = 24 (AC is given as 48)
18 is a given length
AB = sqrt(24^2 + 18^2) = sqrt(576 + 324) = sqrt(900) = 30
Step Two
Find the length of AD
AD = sqrt(32^2 + 24^2) = sqrt(1024 + 576) = sqrt(1600) = 40
Step Three
Find the Perimeter.
P = 2 * 30 + 2*40 = 60 + 80 = 140
P = 140 <<<<< Answer
Answer:
<h2>A 50 HI PO SA FOR THE FIRST TIME IN MY LIFE AND </h2>
"A quadrilateral with both pairs of opposite sides parallel and all sides the same length, i.e., an equilateral parallelogram."
Answer:
AD = 85
Step-by-step explanation:
AD = AB + BC + CD ( substitute values , noting AB = CD = 20 ) , then
AD = 20 + 45 + 20 = 85
0.3(12y)
= 3.6y
hope this helps :)
