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levacccp [35]
3 years ago
14

Please help me with numbers 9 and 11.

Mathematics
1 answer:
hammer [34]3 years ago
4 0
9 is 60000
and 11 is 600km is larger 
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Natalie and Juan collect marbles. The number of marbles that Natalie has is 4 more than
vekshin1

Answer:

it is od 4m- 3

Step-by-step explanation:

8 0
3 years ago
find (a) the area and (b) the circumference of each circle using π=3.14. Round to the hundredths' place. 1. the diameter of the
Arada [10]

area = pi x r^2

circumference = 2x pi x r or pi x d

1st one diameter = 9.5 cm

so radius = 9.5/2 = 4.75

area = 3.14 x 4.75^2 = 70.85 square cm

circumference = 3.14 x 9.5 = 29.83 cm


2nd one radius = 4

area = 3.14 x 4^2 = 50.25 square cm

circumference = 2 x 3.14 x 4 = 25.12 cm

5 0
3 years ago
Read 2 more answers
Can someone help me with this question
Scorpion4ik [409]

Answer:dee

Step-by-step explanation:

dezzz nuts

3 0
3 years ago
A culture started with 1,500 bacteria. After 5 hours it grew to 2,300 bacteria. How many bacteria with be present after 12 hours
Fynjy0 [20]

Answer:

4185

Step-by-step explanation:

A culture of bacteria grows exponentially according to the following general exponential growth function;

P_{t}=P_{0}e^{kt}

where;

p(t) is the population at any given time t.

p(0) is the initial population

k is the growth constant

From the information given we have;

p(0) = 1500

at t = 5, p(t) = 2300; p(5) = 2300

We shall use this information to determine the value of k;

2300=1500e^{5k}

Divide both sides by 1500;

\frac{23}{15}=e^{5k}\\\\ln(\frac{23}{15})=5k\\\\k=0.08549

Therefore, the population of the bacteria at any time t is given by;

P_{t}=1500e^{0.08549t}\\\\P(12)=1500e^{0.08549(12)}=4184.3

8 0
3 years ago
Scores for a common standardized college aptitude test are normally distributed with a mean of 496 and a standard deviation of 1
Sloan [31]

Answer:

0.3257

Step-by-step explanation:

Given an approximately normal distribution:

Z = (x - mean) / standard deviation

Mean = 496 ; Standard deviation = 110

For :

P(x > 545.7)

We obtain the standardized, Z score

Z = (545.7 - 496) / 110

Z = 49.7 / 110

Z = 0.4518

Hence, using the Z distribution table :

P(Z > 0.4518) = 1 - P(Z < 0.4518)

P(Z > 0.4518) = 1 - 0.67429

P(Z > 0.4518) = 0.32571

5 0
3 years ago
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