The right triangle on the right is a scaled copy of the right triangle on the left. Identify the scale factor. Express your answ
1 answer:
Answer:
The images of the question are missing, I found a matching question and image online, and it is in the attachments.
Answer:
The scale factor of the triangles from the left to the right is 2
or
The scale factor of the triangles from the right to the left is 1/2
Step-by-step explanation:
From the image, the right triangle on the left has the following dimensions:
Hypotenuse = 10
length of one side = 10
While the right triangle on the right has the following:
Hypotenuse = 20
Length of one side = 20
From the dimensions above it can be seen that the triangle on the right has a dimension of 2 times the triangle on the left:
Left (10) × 2 = right (20)
Therefore the scale factor of the triangles from the left to the right is 2
or
The scale factor of the triangles from the right to the left is 1/2
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Answer:
Step-by-step explanation:
Consider similar triangles BMC and KMN.
In these triangles,
where O is the point of intersection of BC and MP.
Note that segment OP has the length the same as the side of the square ABCD. Hence,
All the numbers in the first equation have a common factor of 2. Removing that gives
.. x +4y = 6
making it easy to solve for x
.. x = 6 -4y
My choice would be to solve for x using the first equation.
_____
On second thought, it might actually be easier to solve either equation for 8y. That term then directly substitutes into the other equation (equivalent to adding the two equations).
.. 8y = 3x -11 . . . . . from the second equation
.. 2x +(3x -11) = 12 . . . substituting into the first equation
.. 5x = 23 . . . . . . . . . . collect terms, add 11 (what you would get by adding the equations in the first place)
.. x = 4.6
.. y = (3*4.6 -11)/8 = 0.35
.. x +4y = 6
making it easy to solve for x
.. x = 6 -4y
My choice would be to solve for x using the first equation.
_____
On second thought, it might actually be easier to solve either equation for 8y. That term then directly substitutes into the other equation (equivalent to adding the two equations).
.. 8y = 3x -11 . . . . . from the second equation
.. 2x +(3x -11) = 12 . . . substituting into the first equation
.. 5x = 23 . . . . . . . . . . collect terms, add 11 (what you would get by adding the equations in the first place)
.. x = 4.6
.. y = (3*4.6 -11)/8 = 0.35