PLZ HELP I DONT UNDERSTAND A password for a security system must consist of a eater followed by two digits. How many possible pa
sswords are there?
1 answer:
Answer:
7020
Step-by-step explanation:
The letter could be any 1 of the 26 and it could be placed in any 1 of 3 places so this makes 26*3 = 78 possibilities.
For each of these there is any one of permutations of 2 digits from 10
= 10P2 = 10! / 8! = 10*9 = 90.
So the answer is 78 * 90 = 7020.
Note I am assuming that the 2 digits picked are different - no duplicates.
please mark me brainliest!
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