4 years ago

Evaluate 15/r when r=5

Mathematics

1 answer:

strojnjashka [21]4 years ago

3 0

So do 15/5 and the answer is 3.

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Murrr4er [49]

Answer:

Critical value is 1.318 and the confidence interval is 29.357 to 33.042

Step-by-step explanation:

n = 25

x = 31.2

s = 6.99

Degree of freedom = n-1= 25-1 =24

Confidence level = 0.8

So, α = 1- 0.8= 0.2

t critical = $t_{\frac{\alpha}{2},df}=t_{\frac{0.2}{2},24}=t_{0.10,24}=1.318$

Formula of confidence interval : $\bar{x}-t_{\frac{\alpha}{2},df} \times \frac{s}{\sqrt{n}}$ to $\bar{x}+t_{\frac{\alpha}{2},df} \times \frac{s}{\sqrt{n}}$

Confidence interval : $31.2-1.318 \times \frac{6.99}{\sqrt{25}}$ to $31.2+1.318 \times \frac{6.99}{\sqrt{25}}$

Confidence interval : $29.357$ to $33.042$

Hence critical value is 1.318 and the confidence interval is 29.357 to 33.042

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3 years ago

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Answer:

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4 years ago

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